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Chemistry: Post your doubts here!

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The question says: "Which chlorine compound has bonding that can be described as ionic with some covalent character?"
AlCl3 is actually a covalent compound, it's NOT ionic. Aluminium OXIDE, which reacts with both acids and bases, lis amphoteric.
NaCl when dissolved in water forms a solution with pH of 7. It forms Na+ ions and Cl- ions. It is completely ionic. AlCl3, being covalent (and not ionic), hydrolyses in water and forms Al(OH)3 and HCl. The resulting solution has a pH of 3.
MgCl2 can be described as ionic but forms a solution with pH of 6.5 when dissolved in water. The slight acidity is attributed to the slight covalent character.
So again, AlCl3 cannot be described as ionic, rather it is a covalent compound. So the right answer is MgCl2.

The reason for covalency in AlCl3 is the high charge density of Aluminum ion, and large electron cloud of chlorine atom. Aluminum fluoride, for example, is ionic, since fluorine electron clouds are not large enough to be polarised by aluminum ion.
Thankyou sooooo much!! :D
 
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it cant be option A or D .. and the only 2 choices are B and C ..
as u see ... Sulfuric acid is a dehydrating agent and there fore dehydrates Alcohol to alkene ...
And we also know that Alkenes reacts with Sulfuric acid therefore we purify them with dilute NaOH ie option C
What would be the products formed in each case?
Could you write the equations please?
 
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why is it A ?:s why are other options wrong?
 

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The answer is B.
When heated strongly, both carbonates will decompose into their respective oxides and carbon dioxide.

Option 1: Magnesium oxide is a well-known refractory material. This is correct.
Option 2: Both oxides are basic, so they will react with acidic impurities. This is correct.
Option 3: Metallic oxides do not react with each other in redox reactions. The cations present are Ca2+ and Mg2+. To reduce others these cations must get oxidised. There are no such cations asCa3+ or Ca4+, so these cations cannot be oxidised. This is incorrect.

Therefore, the answer is B.
 
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