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No probsThank you!
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No probsThank you!
Umm,How did u convert grams to moles?
Thoda achi tarah se samjaoconc in g per dm^3 = conc in mol * Mr
so conc in mol= conc in g per dm^3 / Mr
Ohh Thanks!Umm,
Mass = Moles * Mass of 1 mole (Molar Mass)
So moles = mass / mass of 1 mole right?
now put values simple
And there are some days that a mind is blank..........Thoda achi tarah se samjao
Muje bhi samaj nahi aya usko kya ayega :/
You have teaceers, I didn't have teacher of chemOhh Thanks!
I did not have a good teacher in my AS....and she did not even touch upon the chapter of moles saying that its easy..and just read from the book...I got a C in my May/June session and I am,pretty much self studying, repeating to get a better grade... Thanks for the help.
And there are some days that a mind is blank..........
Q3.
Ti+ --> Ti3+ + 2e-
moles of Ti+ : moles of e- : moles of VO3-
0.003 moles : ? : 0.002 moles
3 moles : ? moles : 2 moles
Using the half equation, we can see that 3 moles of Ti+ will transfer 6 moles of electrons to 2 moles of VO3-.
In other words, 1 mole of VO3- gains 3 moles of electrons (its oxidation number would decrease by 3 units).
Original oxidation number of vanadium in VO3- is +5, final oxidation number would then be +2 (since it decreases by 3 units).
Q15.
NH3 is a stronger base than H2O, so we have NH3 accepting protons from H2O
NH3 + H2O <--> NH4+ + OH-
Q23.
Using cold dilute KMnO4, we will add OH to each of the carbons across the C=C double bonds.
Q27.
It should be a tertiary alcohol as it is not oxidized. The carbon holding the OH is expected to be joined to 3 other branches containing different number of carbons.
......C
C2-C-C3
.....OH
Q38. Which option are you unsure of? See if you can google for the mechanism of the reaction.
Q39.
Option 1 is correct
CH3CH2CH2OH (alcohol) can be oxidized to CH3CH2CO2H (acid)
CH3CH2CH2OH (alcohol) and CH3CH2CO2H (acid) can undergo esterifcation to form the desired product.
Option 2 is correct
CH3CH2CHO (aldehyde) can be oxidized to CH3CH2CO2H (acid)
CH3CH2CHO (aldehyde) can be reduced to CH3CH2CH2OH (alcohol)
CH3CH2CH2OH (alcohol) and CH3CH2CO2H (acid) can undergo esterifcation to form the desired product.
achaw?Thoda achi tarah se samjao
Muje bhi samaj nahi aya usko kya ayega :/
Sahi to bolaachaw?
Classified papers meansDoes anyone know where can i find a classified past paper for unit 1 ?
Thanks in advance
I mean topic wiseClassified papers means
Oh yeah! There is a thread which contains topical answers( topic wise) Will give you link after some hours! In hurry to school right nowI mean topic wise
https://www.xtremepapers.com/commun...ok-free-download-post-your-doubts-here.33074/I Scored a U in chemistry AS practicals although my components for paper 1 and 2 were an A and a B. I practiced Paper 3 a lot and yet me and all of my friends scored the same grade. Can anyone give me some tips to follow to score an A grade or a B grade for my paper 3
No probsThank you so much
Sorry but I havhi ,
for an example
http://www.cie.org.uk/images/157296-november-2012-question-paper-43.pdf
question number 7 iii
I can solve the 7 i and ii
and from the question i know there will have 2 -CH3 group and 2-CH2 group
and one of the element beside C and H is O
and according to chemical shift ,
there is some group in ~around 1 and 2.5
but everytime i cant find something fit to information
here is the data booklet :
http://fmcapechemistry.weebly.com/uploads/5/6/3/3/5633072/chem_data_booklet.pdf
Sorry I cant help you, because I havnt done the applications part. I thought you were talking about the electrolysis part. So sorry I couldnt help you.Hope you find what your looking for.hi ,
for an example
http://www.cie.org.uk/images/157296-november-2012-question-paper-43.pdf
question number 7 iii
I can solve the 7 i and ii
and from the question i know there will have 2 -CH3 group and 2-CH2 group
and one of the element beside C and H is O
and according to chemical shift ,
there is some group in ~around 1 and 2.5
but everytime i cant find something fit to information
here is the data booklet :
http://fmcapechemistry.weebly.com/uploads/5/6/3/3/5633072/chem_data_booklet.pdf
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