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there are 0.44 mol of Ag+ so there are 0.44 mol of Fe2+http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w11_qp_11.pdf
q9
why wont we use the moles of Fe+3 also, like
why wont it be
0.56^2/0.44^2
it means out of 1 mol o.44 remain, rest of them have been converted into Ag and Fe3+
so there are 1-0.44=0.56 mol of Fe3+ and 0.56 mol of Ag
Kc=0.56*0.56 / 0.44*0.44 = 1.62