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Chemistry 43!!! How was it?!!

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The paper was difficult, in organic section most of the A2 stuff doesn't come out, but its easy for section B though
 
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Im totally devastated. It was difficult! Time was a problem.. What do you all think?
same with me..i got most of it in the 4th qs only 3 marks are wrong but 5th qs i got 4 marks wrong..i think section b was very easy..but i screwed in the 1st qs of section A..
 
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Based on past gt, for paper 4, Grades to get A,
May June,
-2007 -> 64
-2008 -> 65
-2009 -> 65
-2010 -> 54
-2011 -> 59
-2012 -> 55

OCT NOV,
-2007 -> 65
-2008 -> 67
-2009 -> 64
-2010 -> 59
-2011 -> 69

gt for OCT NOV 2012 could be around 60<A<65 based on the difficulty of MJ 2012 paper and OCT NOV gt's.
 
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only if i memorize the pastyears that i did, i could have collected some easy / small marks. :( so overall it was d i f f i c u l t.
 
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Based on past gt, for paper 4, Grades to get A,
May June,
-2007 -> 64
-2008 -> 65
-2009 -> 65
-2010 -> 54
-2011 -> 59
-2012 -> 55

OCT NOV,
-2007 -> 65
-2008 -> 67
-2009 -> 64
-2010 -> 59
-2011 -> 69

gt for OCT NOV 2012 could be around 60<A<65 based on the difficulty of MJ 2012 paper and OCT NOV gt's.
but wasnt this more difficult than may/june?
 
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but wasnt this more difficult than may/june?
I find that May June is more about memorizing, I guess memorizing is difficult? but for me I'm more okay with memorizing.

NOTE: I found something suspicious, the MJ 41/2011 paper is similar to what OCT NOV paper set.
 
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What was the organic compound with 20+ carbons? I can't remember.
-The compound I drawn was 2 ketone groups, with 2 ester bonding, with 2 aryl group all attached together.
-The compound name start with 'c'

Can anyone guess or remember?
 
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This is the compound that I roughly drawn,
 

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This is the compound that I roughly drawn,
I have drawn two alkenes instead of two ester bonds because hot concentrated KMnO4 was used to break them. And in the middle of the two aryl groups it was -C=CH-CO-CH2-CO-CH=C-
 
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I have drawn two alkenes instead of two ester bonds because hot concentrated KMnO4 was used to break them.
That's what I thought, they also said that this would react with 2,4-dnph, so it could be carbonyl, but ketone can't oxidize further, narrowing down the results, it could be aldehyde group.
 
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