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.... me also got it wrong the first time ... lets hope they do not give anything out of the given syllabus this time 
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1st question:
Now, for 3 springs in parallel, the extension is x. So the extension for a SINGLE spring would have been 3x for a load of W.
NOW, for 2 springs in parallel the extension for a load of W = 3x/2
now, FOR A LOAD OF 2W the extension for those 2 springs would quite obviously be 2* 3x/2= 3x
2nd question:
It said the current was DECREASED UNIFORMLY. So, we can take the AVERAGE current during that time period. So charge = average current * time (do the calculation now from here
Hope I could help you boss.
Yeah, from O-levels.
We didn't study it in AS level and there's a good possibility people forgot it. Good thing I have Chemistry too, because we learn a formula relating to heat capacity with that. 
Q11)
An outer edge (i.e. X and Y) will always stretch (tension) while an inner edge (Z) will always compress (compression), so the answer is B. There was a question which utilized this concept in one of the P2 papers, but I don't remember which one it was exactly.
Jazakallah. Thank you very much for help. May Allah bless you.Q11)
Momentum has to be conserved, so.
Initial momentum = Final momentum
Initial is 0 and at final, they move in opposite directions, so..
0 = M1V1 - M2V2
M2V2 = M1V1
V1/V2 = M2/M1
Q36) In this, the first 10 Ohm resistor which is perpendicular from X to Y is in parallel with the 3 other 10 Ohm resistors (total = 30), so the combined resistance is the inverse of:
(1/10) + (1/30) = 7.5 Ohm which is between 1 and 10 Ohm.
Q37)
X is connected directly with the voltmeter so if the potentiometer is at point X, the voltmeter will always read 4.0 V. If you move to Y, then you can apply the potentiometer formula to calculate the current.
V = 4 * (10/20) = 2 V
So At X, V = 4
At Y, V = 2
B is the only graph that suits this.
There is just one problem, though. For question 37, the answer is A.Q11)
Momentum has to be conserved, so.
Initial momentum = Final momentum
Initial is 0 and at final, they move in opposite directions, so..
0 = M1V1 - M2V2
M2V2 = M1V1
V1/V2 = M2/M1
Q36) In this, the first 10 Ohm resistor which is perpendicular from X to Y is in parallel with the 3 other 10 Ohm resistors (total = 30), so the combined resistance is the inverse of:
(1/10) + (1/30) = 7.5 Ohm which is between 1 and 10 Ohm.
Q37)
X is connected directly with the voltmeter so if the potentiometer is at point X, the voltmeter will always read 4.0 V. If you move to Y, then you can apply the potentiometer formula to calculate the current.
V = 4 * (10/20) = 2 V
So At X, V = 4
At Y, V = 2
B is the only graph that suits this.
Q9)more questions please do help. may Allah bless you.
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_qp_11.pdf
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_ms_11.pdf
questions 9, 10, 14, 31, and 35. thanks once again.
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