AS Physics P1 MCQs Preparation Thread.

[xxfarhaxx]

http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s06_qp_1.pdf

how do we do q33. is the circuit parallel?

k acrross 500 ohm da pd is 4v..n acrs da 2000 ohm da pd is 8v..so da pd is across x n y is 8-4=4v..

 

[raamish]

k acrross 500 ohm da pd is 4v..n acrs da 2000 ohm da pd is 8v..so da pd is across x n y is 8-4=4v..

ok so across X if we are to find the p.d we take the whole line then right? and its a series circuit right not a parallel one?

 

[omg]

no idea mate... well this is what examiner report has to say...
Question 25 proved to have the lowest facility, 0.32, of the entire paper. If only candidates had used their
pencils to draw in, on the paper itself, the new wave a little bit later in time they would have seen clearly that
P must go down and that Q barely moves - if they tried Q down as well they would not have been able to
give that as an answer because it is not there.

er didnt prov 2 b hlpful :/

 

[omg]

http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_w07_qp_1.pdf
q.16 and 31 plsss

 

[umarashraf]

er didnt prov 2 b hlpful :/

yeah i know... i have no clue about this.. my initial ans was B...

 

[bloody_mary]

how 2? :/
i hv a hard copy

oh ok

 

[xxfarhaxx]

ok so across X if we are to find the p.d we take the whole line then right? and its a series circuit right not a parallel one?

ya to find da individual pd across da resistors u use da series circiut..
to find across X n Y, use da parallel circiut n subtract thm

 

[umarashraf]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w07_qp_1.pdf
q.16 and 31 plsss

for 16.. the string is stretched full.. so no further downward movement will be observed... this shows minimum kinetic energy... the string is fully stretched, so it has maximum elastic potential energy... ( energy possessed by a body by virtue of compression or stretching.. )

 

[omg]

q.4 any1

 

[umarashraf]

q.4 any1

i dont have the marking scheme of this pap.. is the ans B...???

 

[leosco1995]

THANKYOU
are u havin ms of 1997 and 1998??
i just found those pprs bt dun hv the ms :/

If you have the papers, please post them. Maybe we could discuss the answers.

 

[omg]

http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_w10_qp_12.pdf
q.8 and 25

 

[omg]

i dont have the marking scheme of this pap.. is the ans B...???

yesssssssssssssssss
solution???

 

[omg]

If you have the papers, please post them. Maybe we could discuss the answers.

iv gotta hard copy :/

 

[omg]

i dont have the marking scheme of this pap.. is the ans B...???

if u need the ms, here it is

 

[bloody_mary]

People needs loads of help here! thanks!

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s09_qp_1.pdf
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s09_er.pdf
Q 10, 15 & 18. How to solve them?
Q19 I think answer should be D. cant be B or C. btw aluminium and steel. steel will sustain largest deformation since its an alloy, mixture of metals, so will be stronger than aluminum alone rite?

Q10
well first right what we will now
so X: 0.5mv^2=E
and Y: has 0.5*2m*l^2 (l is the speed because it can't be same as X has)
since it is an explosion they both have same KE so will try to find l for Y
so l= sqrt(E/m)
v= sqrt(2E/m) now divide l by v so we get l is sqrt(0.5)*v

no put l back in equation for Y and we get 0.25mv^2
and X will be 0.5mv^2

now divide X by Y to get 2/1

Q15
PE =mgh
when both vessel are the same that means h is halved but since h is halved so is m

so 0.5m * 0.5h *g gives 0.25mgh which is B

Q18
I can't figure out

Q19
Steel is strong (opposes deformation) but not as ductile as aluminium and that is why it used in planes

 

[bloody_mary]

help me out too pls

in what??

 

[bloody_mary]

can someone please help me with questions:
15
26
28
30
31

http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_w11_qp_12.pdf
http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_w11_ms_12.pdf

thanks in advance

 

[umarashraf]

yesssssssssssssssss
solution???

remove 3 and sin from the eq has they have no units... this gives you L(a^2/P)=QT^2
now put their units.. m(m^2/P)=Qs^2.. by solving this, u will have QP=m^3/s^2... or m^3s^-2.... now search through the answers whose product can give you m^3s^-2.. and its B.. (m^2) * (ms^-2)

 

[leosco1995]

Could anyone answer the question in the attached image? The answer is A but I don't get it.