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Hey can anyone help me with mcq no : 6 ? its really important i fail to understand such things :/
They asked about each pulse, so u see it each pulse takes 2 squares--> 2 cm and since timebase setting is 1, so 1*2=2 microseconds
33--> as simple as that! strain increases means length increases increasing resistance as well.. no need to even think about the cross sectional area..
34--> Sorry I am not sure about this. h4rriet please help!
17--> they said 93% is heat while 7% is light... so 93+7=100... answer is simple 7% ((7/100)*100) - I guess, thats how i understood it..
U have to find R first. R=V/Ihe is the superman of the xtremepaper
U have to find R first. R=V/I
At point A B and D, ratio of V:I will be higher as V is more than I so ratio will be higher than 1. At C they are almost equal so ratio will almost be 1 so its the smallest value of R
u dont have to find it quantitatively. just take ratios. Ratio of V:I is smallest for C so R is smallestno datas given . how to find r ? >
Q .. if ratio of power of x / power of y is 2 ...mcq22...first calculate density =mass/volume, then use density= cuberoot volume to calculate the distance u will get C...
mcq 8...using v1= a*t1
v2 = a*t2
then use 2as= (v2)^2 - (v1)^2
or else use this method , in vertical case lyk this one u need to knw that s= 1/2 at^2 is used...
put values in this eq nd u vl get 2h/(t2^2 - t1^2)
hope u get these...
mcq22...first calculate density =mass/volume, then use density= cuberoot volume to calculate the distance u will get C...
mcq 8...using v1= a*t1
v2 = a*t2
then use 2as= (v2)^2 - (v1)^2
or else use this method , in vertical case lyk this one u need to knw that s= 1/2 at^2 is used...
put values in this eq nd u vl get 2h/(t2^2 - t1^2)
hope u get these...
Q .. if ratio of power of x / power of y is 2 ...
what will be the ratio of resistance of x /resistance of y ...
ans is 4 .. but i couldnt get the hint using p=I^2R
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w09_qp_12.pdf
q4,8,9,12,13,18,20,21
this paper was a tough one please help me with these someone?
mcq 4: use 2as= v^2 - u^2
2* (-0.2)*(1000) = 0^2 - u^2 solve u will get A
can u plz give me the link to this qts .....
mcq22...first calculate density =mass/volume, then use density= cuberoot volume to calculate the distance u will get C...
mcq 8...using v1= a*t1
v2 = a*t2
then use 2as= (v2)^2 - (v1)^2
or else use this method , in vertical case lyk this one u need to knw that s= 1/2 at^2 is used...
put values in this eq nd u vl get 2h/(t2^2 - t1^2)
hope u get these...
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