AS Physics P1 MCQs Preparation Thread.

[h4rriet]

i am using 2as=v2-u2 for 9 but cant get the answer.rest is understood.thanks

Here's a way of doing it: s=u^2/2a. Assume that u = 300 and a = 50. s will then = 900. Increasing 300 by 20% will make it 360. If a stays the same, s = 1296. 1296/900=1.44.

 

[h4rriet]

Is the zeroth order considered a maxima?
And can you please explain no 24 from s10 p11?

The centre of the screen is always a maximum because the path difference of the waves = o so they're exactly in phase.

 

[abruzzi]

Use v^2=u^2+2as. a=F/m. To find F, draw a free-body diagram on the 1 kg mass, and m will be 3 kg.

Thanks a tonne

 

[itallion stallion]

Here's a way of doing it: s=u^2/2a. Assume that u = 300 and a = 50. s will then = 900. Increasing 300 by 20% will make it 360. If a stays the same, s = 1296. 1296/900=1.44.

why are we doing this 1296/900?

 

[h4rriet]

why are we doing this 1296/900?

To compare the distances.

 

[Raweeha]

The centre of the screen is always a maximum because the path difference of the waves = o so they're exactly in phase.

Does that also apply while using 'n x lambda= d sin theta' ?
So you have to add one to whatever answer you for n?

 

[Raghad Dia]

Can someone explain M/J 2003 #11 for me please

 

[Mairaxo]

Can someone explain M/J 2003 #11 for me please

road has an upward force on wheel as it is the opposing force to the weight of the car so it is either A or B. The car moves towards the right so the road applies a force on the wheels to the right making it able to move so the answer is B.

 

[itallion stallion]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w10_qp_12.pdf.how to do q7,15,21(never understood these type of question).thanks!!

 

[itallion stallion]

why are we doing this 1296/900?

thanks alot!!

 

[itallion stallion]

how is this question going to be solved:a wire stretches 8mm under a load of 60N.what will be the extension of a wire of same material having four times the cross sectional area and twice the original length.when the same load is applied.answer is 4mm

 

[h4rriet]

Does that also apply while using 'n x lambda= d sin theta' ?
So you have to add one to whatever answer you for n?

sin will be zero for the middle maximum.

 

[sweetjinnah]

how is this question going to be solved:a wire stretches 8mm under a load of 60N.what will be the extension of a wire of same material having four times the cross sectional area and twice the original length.when the same load is applied.answer is 4mm

okay...force is same
let it be...Wire X Wire Y
F=60 N F=60 N
e= 8 mm ext.y=?
A 4A
lx= l ly=2l
cz the two wires r of da same material both have same Young Modulus
E of x = E of y
Fl/Ae = Fl/Ae
put the values nd solve u will get e=4 mm....
Hope u understood....

 

[Cesar_malik]

9702/12/O/N/11

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w11_ms_12.pdf
Mcq 36 the sinusodial wave form
Anyone ???? Please
Thanks

 

[sweetjinnah]

9702/12/O/N/11

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w11_ms_12.pdf
Mcq 36 the sinusodial wave form
Anyone ???? Please
Thanks

mcq 36 doesnt have any wave form....??

 

[Cesar_malik]

B

mcq 36 doesnt have any wave form....??

Very sorry i meant 26 thanks

 

[itallion stallion]

y

okay...force is same
let it be...Wire X Wire Y
F=60 N F=60 N
e= 8 mm ext.y=?
A 4A
lx= l ly=2l
cz the two wires r of da same material both have same Young Modulus
E of x = E of y
Fl/Ae = Fl/Ae
put the values nd solve u will get e=4 mm....
Hope u understood....

yeah got it. thanks alot

 

[itallion stallion]

okay...force is same
let it be...Wire X Wire Y
F=60 N F=60 N
e= 8 mm ext.y=?
A 4A
lx= l ly=2l
cz the two wires r of da same material both have same Young Modulus
E of x = E of y
Fl/Ae = Fl/Ae
put the values nd solve u will get e=4 mm....
Hope u understood....

what to do in this one:The youngs modulas of steel is determined using a length of steel wire and is found to have value of 'E'.another experimentis carried out using a wire of same steel,but twice the length and half the diameter.what value is obtained for the youngs modulas in the second experiment.

 

[sweetjinnah]

what to do in this one:The youngs modulas of steel is determined using a length of steel wire and is found to have value of 'E'.another experimentis carried out using a wire of same steel,but twice the length and half the diameter.what value is obtained for the youngs modulas in the second experiment.

the second wire will also have young modulus: E because the seconnd wire is also made of the same material nd the length nd diameter r only given to confuse ppl....

 

[Amber]

http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_s05_qp_1.pdf

Question 25 pls