Addmaths paper 1

[Shadow]

It could be done without substitution, you just had to deal with (-sin Q - cos Q) as one whole. I did not find it appropriate to follow working in this way so I substituted x.

I dont think i vil b getting marks on that one ... I just solved it sumhow, n wrote 'Proved' in the end

 

[Saad Mughal]

I dont think i vil b getting marks on that one ... I just solved it sumhow, n wrote 'Proved' in the end

I didn't write proved.

 

[Saad Mughal]

Would it get two or two would be cut...?
I wrote the gradient as 2 instead of 1/2 and then multiplying by 6 coz i was in a hurry lol...
And how much in The Binomial ques?

You'd get 2 I think.
In binomial, for second part. 1 mark.

 

[Shadow]

I didn't write proved.

No prob ... u dont suppose i wud be getting a mark for writing 'Proved'

 

[Ammarfasih]

Did you do b^2 - 4ac = 0?

yes

 

[Saad Mughal]

yes

You'll get Half marks.

 

[Shadow]

yes

it was supposed to be - b2 - 4ac < 0

 

[Shadow]

How did p2 go guys? Lets just discuss it here in the same thread 2mrw

 

[Saad Mughal]

How did p2 go guys? Lets just discuss it here in the same thread 2mrw

But I've made a thread for it.

 

[mohdumar]

For the k, gradient and binomial, you'll only get partial credit for k and binomial. 1-2 marks for the gradient one.
Ok so, I let x = -sin Q - cos Q.
Then,
=(1+x)^2 - 2(1-cos Q)(1-sin Q)
=1 + 2x + x^2 - 2(1-sin Q - cos Q + sin Q cos Q).
=1 + 2(-sin Q - cos Q) + (-sin Q - cos Q)^2 - 2 + 2 sin Q + 2 cos Q - 2 sin Q cos Q
=1 - 2 sin Q -cos Q + sin^2 Q + 2 sin Q cos Q + cos^2 Q - 2 + 2 sin Q + 2 cos Q - 2 sin Q cos Q
Rearranging all the terms correctly,
=1-2 -2 sin Q + 2 sin Q - 2 cos Q + 2 cos Q + 2 sin Q cos Q - 2 sin Q cos Q + (sin^2 Q + cos^2 Q)
=-1 + (1)
=0

I shifted one half of equation to rhs to form identity, then expanded LHS then factorized to form RHS!!!

 

[Saad Mughal]

I shifted one half of equation to rhs to form identity, then expanded LHS then factorized to form RHS!!!

Lol. That shouldn't be an issue.

 

[Shadow]

But I've made a thread for it.

Oops ... ok den, chalo saare