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Add maths paper 1 discussion.
- Thread starter Daharki009
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ok guys do u think i'll loose method mark for not using the nCr formula for the binominal....
i feel stupid asking this but u see i just expanded the term instead and this has been bugging me...
i feel stupid asking this but u see i just expanded the term instead and this has been bugging me...
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Does anyone else remember the ans to da either part of last que??? I remember the coordinates of A which we had to find in the first part were (0,5) .... In the next part we had to find the coordinates of C and D..... For C we had to find the equation of normal at B which meets the x-axis at C... By putting y= 0 into the eq of normal we had to find to coordinates of C. For D we had to simultaneously solve the eq of normal and tangent at x= -1 .... Is my method correct????????? I got 2 unit2 as answer by this method.... If my method is correct how many marks for method will I get out of 7???? Plzz tell me...... Iam very tensed....
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vishal said:
i think the coordinates of A was (-1, 5) maybe thats where u did the mistake and if u got the wrong area but the method was ryt u'll probably loose 3 marks or so.... dont worry too much...
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Is my method correct???? Besides if i have got the coordinates of A wrong so how many marks will I lose in the first part out of 3??? Do u remember the coordinates of C and D ????
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vishal said:
well if ur differentiation was ryt then ull loose the answer mark for a) which is 1 and as far as i remember C was (-5, 0) and D was (20, 5)...
frm what u said ur method seems ryt.... but i cant be sure abt the marks u'll loose... just hope for the best.
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Do u remember the eq: of curve????
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Plzz tell me the eq of curve in the either part????
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the co ordinates of A were 0,5.the coordinates of C were -5,0 .the coordinates of D were 20,5.so the area was 50 sq units.
What did u all get for the value of A??
what was the unit vector parallel to AB??and what was the position vector of C??
i got 24/25,-7/25 as the unit vector and 41,16.5 as the position vector.
the value of K=-2
the combinations were 3003,1050 and 364.
lgy=0.2x+2
a=100 and b=0.2
the radius was 15 and the shaded area was 105.1
A=1/6
stationery point was 1,-9
the angles were 19.5,160.5 and 25.7,115.7 and pi/2 ,7pi/6
AM I CORRECT???
What did u all get for the value of A??
what was the unit vector parallel to AB??and what was the position vector of C??
i got 24/25,-7/25 as the unit vector and 41,16.5 as the position vector.
the value of K=-2
the combinations were 3003,1050 and 364.
lgy=0.2x+2
a=100 and b=0.2
the radius was 15 and the shaded area was 105.1
A=1/6
stationery point was 1,-9
the angles were 19.5,160.5 and 25.7,115.7 and pi/2 ,7pi/6
AM I CORRECT???
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123add u r absolutely correct..... Plzz read my above post abt the either part area and plzz tell me how many marks will I lose for wrong area and correct method hopefully ???? Plus if u remember the eq of curve do tell me....
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vishal said:
3x^3 + 2x^2 -5x +1
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123add1 said:
the unit vector was (24/25 , -7/25)
and the position vector of C was (sth, -16.5)
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Are u sure abt this eq???? Because at x=-1 the y coordinate is 9 bt as far as I remember the y coordinate of A was 5.....
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vishal said:
check again, 3x^3 +2x^2 -5X +1 when x= -1 y is 5
if that is so how can A be (0, 5).... isnt is suppose to be (-1, 5)
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No I guess u dnt remember the question.... We were supposed to tell the coordinates of the point where the tangent to the curve at x= -1 meets the x axis.... This was point A. So the coordinates of A were (0,5) .....
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yes my mistake it was -16.5.typing mistake :lol:
and about the coordinates of A.
A was on the Y -AXIS >>>>
the tangent at x=-1 cut at A which was on the y axis.and the equation of the tangent was y=5.
and about the coordinates of A.
A was on the Y -AXIS >>>>
the tangent at x=-1 cut at A which was on the y axis.and the equation of the tangent was y=5.
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Yeah sorry it was x axis.... I made a calculation mistake in finding the coordinates of C and D....and hence got the area wrong.... How many marks will I lose 4 dis out of 7???? My method was right.....,it was only a calc mistake.... Plzzzzzzzzz 123add tell me .....
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The mistake made was I wrote -1= 1/5x as -1/5 instead of -5 .... And did da same mistake for finding the coordinates for D.... How many marks will I loose out of 7???