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A2 physics p4 o/n 08 help pls

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hello
can someone pls explain me question
1aiii),b)
7ci),ii)


thanks in advance.
 
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1aiii). Reaction force is the resultant force. Therefore the answer is : GMm/(R)2 - mR(w)2 , according to the questions (ai & aii).
1bi). The equatorial diameter is more than the polar diameter. Hence the radius is constantly changing. Therefore the normal reaction
has different values at the poles & the equator.
1bii) 1. Use the formula, a=r(w)2
2. At the poles the component of radius becomes zero, therefore acceleration is also zero.

Hope, it will be useful.
;):whistle:
 
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55
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1aiii). Reaction force is the resultant force. Therefore the answer is : GMm/(R)2 - mR(w)2 , according to the questions (ai & aii).
1bi). The equatorial diameter is more than the polar diameter. Hence the radius is constantly changing. Therefore the normal reaction
has different values at the poles & the equator.
1bii) 1. Use the formula, a=r(w)2
2. At the poles the component of radius becomes zero, therefore acceleration is also zero.

Hope, it will be useful.
;):whistle:

aiii) I believe the centripetal force is the resultant force, which acts towards the centre. Taking that as the positive direction, then centripetal force= gravitational force - reaction force
 
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