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A level Statistics doubt??Post your doubts here!

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Y is 0 if same or greater minus the smaller value of x there Y can only be 0(22 44 66) 2(24 42 46 64) 4(26 62) so for 0 its (.5*.5+.4*.4+.1*.1) for 2 its (.5*.4)*2+(.1*.4)*2 and for 4 its (.5*.1)*2
Y=0 2 4
p y=.42 .48 .1(respectively)
ex = .96.4=1.36
Im still not getting it bro :s
 
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P(X > 2µ) = 0.1016


3µ = 7σ^2
µ = 7/3σ^2

P(X>2u)
P(X>2u-u/SD)
P(z>u/SD)
P(z>(7 SD^2/3 / SD) =0.1016
P(z>7/3 * SD)=0.1016
z<-(7SD/3 )=-invPhi(1-0.1016)
7SD/3 = invPhi(0.8984)
SD = 3*invPhi(0.8984) / 7

Now Mean will be (7*(SD)^2)/3
 
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long method means more time consumption it just leaves less time for other mind draining tasks

naw .. not really :p it just consumes pages for me.. I just hope in the main paper I don't find the time short to solve all the questions!

My target has always been 1 hour for S1. but hardly meet that target:p AND PLEASE PLEASE.. NO PLOTTING OF GRAPHS in the coming paper.. -,- especially the CF.
 
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naw .. not really :p it just consumes pages for me.. I just hope in the main paper I don't find the time short to solve all the questions!

My target has always been 1 hour for S1. but hardly meet that target:p AND PLEASE PLEASE.. NO PLOTTING OF GRAPHS in the coming paper.. -,- especially the CF.
cF rocks but if it doesnt then they will give another question that will make me mad
 
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