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  1. emkay

    Computers & ICT: Post your doubts here!

    is there anyway one can send A2 project privately? =(
  2. emkay

    Countdown to CIE result 22 January 2013

    oh bhains, ab mujhey dar lag raha ae :/
  3. emkay

    Physics: Post your doubts here!

    for 13, Forward force - Frictional Force = Mass*Acceleration Forward Force = 2.0*9.81 Frictional Force = 6N Mass (net)= 8.0 + 2.0 Acceleration = F-f/mass a=19.62-6/10 a=1.36 or 1.4 i.e A is the answer. --- for 15, since tourqe is equal to force*distance, the distance moved by the spindle will be...
  4. emkay

    Physics: Post your doubts here!

    As it says, 3000 revolutions/min (apply unitary method) 3000 = 60sec 1 = x x = 60/3000 x= 0.02s(one wave) in the 10cm wide display of c.r.o looking at the options, the second one showing 10ms means 0.01 and 0.01*2 = 0.02 means one wave and when we multiply 0.02*5 (as there could be 5 waves made...
  5. emkay

    A little confusing.

    Greetings! hey everyone hope you're all doing good :) i'm doing A2 and just wanted to know what is the best way to hop into a uni, entry test or giving SAT? e.g for NUST.
  6. emkay

    A level Computing: Post your doubts here

    as for A's, Yes you can. as i gave it already but for A2 you need assistance on the project as the CIE doesn't accept private projects. or you could just get it verified by some reputed school.
  7. emkay

    Physics: Post your doubts here!

    for minimum force to be applied the angle is always 90 degree. and for second part, Torque = Force*distance Force=Torque/distance F=130/0.45 F=290N
  8. emkay

    PHYSICS P 12. HOW WAS IT??

    i did C *_*
  9. emkay

    PHYSICS P 12. HOW WAS IT??

    what about the polycrystalline and crystalline question? was it C or D?
  10. emkay

    Physics: Post your doubts here!

    for Q4 a ii) Ek = p^2/2m 1/2mv^2 = (mv)^2/2m (since, p=mv) 1/2mv^2= mv^2/2 (m and m cancels out) 1/2mv^2 = 1/2mv^2. (Hence, Proven) for Q4 b i) find change in momentum first, delta p = m*delta v p= 0.035*(4.5+3.5) p=0.28. F=change in momentum/change in time F=0.28/0.14 F=2.0N.
  11. emkay

    PHYSICS P 12. HOW WAS IT??

    ;(
  12. emkay

    Physics: Post your doubts here!

    itney saarey hain, confuse ker k rakh diya hae ;(
  13. emkay

    Physics: Post your doubts here!

    Graphs Graphs Graphs Graphs, STUPID GRAPHS!
  14. emkay

    Physics: Post your doubts here!

    sin theta = 40/50 theta = 53 F= 8Cos53 (Since, there are two components of 4N i multiplied it with 2, 4*2=8)
  15. emkay

    Physics: Post your doubts here!

    the torque between the pulley Q and P in the upper wire is the torque at Q. as it is causing the driving force for Q. i.e T=F*d F= T/d F=3/100*10^-3 F=30*2 (since, the formula suggests force into perpendicular distance between the two forces) F=60 N. Torque on P, T=F*d T=30*150*10^-2 (Force...
  16. emkay

    Physics: Post your doubts here!

    you party crasher! :P why did you multiply it with 100 and made me look like a total idiot? :D
  17. emkay

    Physics: Post your doubts here!

    is the answer A. 5.1 * 10^-4?
  18. emkay

    How should we judge a person!

    how about we don't judge at all? be care-free, easy come easy go. love nobody and feel no pain x)
  19. emkay

    Laptop or tablet???

    LOL. best of luck with the choice-making decision.
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