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Recent content by Muhammad Asif

  1. M

    Chemistry: Post your doubts here!

    only group 1 sulphates and carbonates are soluble
  2. M

    Chemistry: Post your doubts here!

    write the equation of the reaction first.....in a situation u will be given initial and final moles of a reactant or the product or change in moles in reactant or product... if u are given change in moles than do stoichometery from ratios(from the equation) to find the moles at equlibrium...
  3. M

    Chemistry: Post your doubts here!

    bro plx mind that kinda language...+ what i said wasnt wrong.......in OUR CIE we dont use H2 to reduce carbonyl compounds
  4. M

    Chemistry: Post your doubts here!

    H2 isnt used to reduce ketones and aldehydes......
  5. M

    Chemistry: Post your doubts here!

    dude Hydroen n platinum catalyst i used for hydrogenation of alkenes to saturate the thats just E
  6. M

    Chemistry: Post your doubts here!

    you appeared for 12 or 13?????
  7. M

    Chemistry: Post your doubts here!

    i dont think paper 12 was really something tough although some questions were confusing.......... many were repeated from past papers... i didnt got an extraordinary but a nice paper
  8. M

    Chemistry: Post your doubts here!

    How was todays paper every1????
  9. M

    Chemistry: Post your doubts here!

    the number of moles polymers therotically can never be equal to the number of moles of monomer.....so 1 is not the answer thus only option is C
  10. M

    Chemistry: Post your doubts here!

    the thing which is an oxidising agent always gets reduced it self..........................................
  11. M

    Chemistry: Post your doubts here!

    Q22=plymerise 1-2 dichloroethene and then hydrolise it all Cl will be replaced by OH giving the plymer shown...... Q24=the intermediate is a +charged carbocation which react with electrophile Br...thus accepts 2 electrons from it...so acceptor of pair of electrons is a electrophile...
  12. M

    Chemistry: Post your doubts here!

    yes both are oxidising agents thus same result
  13. M

    Chemistry: Post your doubts here!

    the answer is C since the moles of CO2 produced=atoms of CO2: 1mol=24dm3thus 24000cm3 mols that occupy 72cm3=72/24000 moles that occupy72cm3=3*10^-3 so carbon atoms=3*10^-3 mass of this carbon atoms= 3*10^3*12(mr) mass=.036g mass of almunium=mass of compund-mass of carbon atoms mass of...
  14. M

    Chemistry: Post your doubts here!

    the concern is not with which acid you acidify it......the thing is both KMNO4 and K2Cr2O7 are acidifed.....thats it
  15. M

    Chemistry: Post your doubts here!

    its the oxidaton reaction a primary alcohol(if completelyoxidised under Hot concentrated condition) is oxidised 2 a carboxyhlic acid .....if incomplte oxidise(cold dilute) then can form aldehyde.......secondory alcohols are just oxidised 2 ketones in both conditions.....
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