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  1. M

    Chemistry: Post your doubts here!

    only group 1 sulphates and carbonates are soluble
  2. M

    Chemistry: Post your doubts here!

    write the equation of the reaction first.....in a situation u will be given initial and final moles of a reactant or the product or change in moles in reactant or product... if u are given change in moles than do stoichometery from ratios(from the equation) to find the moles at equlibrium...
  3. M

    Chemistry: Post your doubts here!

    bro plx mind that kinda language...+ what i said wasnt wrong.......in OUR CIE we dont use H2 to reduce carbonyl compounds
  4. M

    Chemistry: Post your doubts here!

    H2 isnt used to reduce ketones and aldehydes......
  5. M

    Chemistry: Post your doubts here!

    dude Hydroen n platinum catalyst i used for hydrogenation of alkenes to saturate the thats just E
  6. M

    Chemistry: Post your doubts here!

    you appeared for 12 or 13?????
  7. M

    Chemistry: Post your doubts here!

    i dont think paper 12 was really something tough although some questions were confusing.......... many were repeated from past papers... i didnt got an extraordinary but a nice paper
  8. M

    Chemistry: Post your doubts here!

    How was todays paper every1????
  9. M

    Chemistry: Post your doubts here!

    the number of moles polymers therotically can never be equal to the number of moles of monomer.....so 1 is not the answer thus only option is C
  10. M

    Chemistry: Post your doubts here!

    the thing which is an oxidising agent always gets reduced it self..........................................
  11. M

    Chemistry: Post your doubts here!

    Q22=plymerise 1-2 dichloroethene and then hydrolise it all Cl will be replaced by OH giving the plymer shown...... Q24=the intermediate is a +charged carbocation which react with electrophile Br...thus accepts 2 electrons from it...so acceptor of pair of electrons is a electrophile...
  12. M

    Chemistry: Post your doubts here!

    yes both are oxidising agents thus same result
  13. M

    Chemistry: Post your doubts here!

    the answer is C since the moles of CO2 produced=atoms of CO2: 1mol=24dm3thus 24000cm3 mols that occupy 72cm3=72/24000 moles that occupy72cm3=3*10^-3 so carbon atoms=3*10^-3 mass of this carbon atoms= 3*10^3*12(mr) mass=.036g mass of almunium=mass of compund-mass of carbon atoms mass of...
  14. M

    Chemistry: Post your doubts here!

    the concern is not with which acid you acidify it......the thing is both KMNO4 and K2Cr2O7 are acidifed.....thats it
  15. M

    Chemistry: Post your doubts here!

    its the oxidaton reaction a primary alcohol(if completelyoxidised under Hot concentrated condition) is oxidised 2 a carboxyhlic acid .....if incomplte oxidise(cold dilute) then can form aldehyde.......secondory alcohols are just oxidised 2 ketones in both conditions.....
  16. M

    Chemistry: Post your doubts here!

    in such molecules mostly a chiral centre is found is where 3 line join if any chain isnt the same as other 3
  17. M

    Chemistry: Post your doubts here!

    because Mr of H2=(2*1)=2 moles=mass/mr moles=120/2 moles=60 same for moles at equilibrium
  18. M

    Chemistry: Post your doubts here!

    the equation is N2+3H2----->2NH3 in the start moles of H2=60......... at equlibrium H2 moles=48....thus change in moles=60-48=12 from the equation the ratio of H2:NH3=3:2...............thus moles of NH3 produced would be (2*12)/3=8moles..... Mass=Mr*moles Mass=(14+3)*8 Mass=17*8 Mass=136Kg
  19. M

    Chemistry: Post your doubts here!

    in the orignal molecule there are 9 double bonds if you count them......................in the residue one chain hai 2 double bonds and 2chains have 1 double bond thus total is 4.....so the bonds that are saturated are 9-4=5 I HOPE YOU GET IT NOW
  20. M

    Chemistry: Post your doubts here!

    yes it is as only structured and display formula will show you the position of the bond
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