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we had to explain it as well.GUYS, ANYONE REMEMBER THE SHM QUESTION. VARIENT 42. DID IT SAY STATE AND EXPLAIN HOW THE TROLLEY IS DAMPED ??? OR DID IT SAY '' STATE '' ONLY.. I WROTE ' LIGHTLY DAMPED ' ONLY.
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we had to explain it as well.GUYS, ANYONE REMEMBER THE SHM QUESTION. VARIENT 42. DID IT SAY STATE AND EXPLAIN HOW THE TROLLEY IS DAMPED ??? OR DID IT SAY '' STATE '' ONLY.. I WROTE ' LIGHTLY DAMPED ' ONLY.
http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-5.html read the explanation for Q34ii. it says"that since the gradient is in opposite directions emf would be in opposite direction to but in paper the gradient was in same directionThe gradient was in the same direction but one line was passing through positive values of B and other through -ve.
So wont they be in opposite directions? Does sign of B make any difference?
ik thaz wut made me draw the peaks in opposite directionsThe gradient was in the same direction but one line was passing through positive values of B and other through -ve.
So wont they be in opposite directions? Does sign of B make any difference?
because both gradiants are negative. So in the same direction the second line was steeper so the peek is larger.ik thaz wut made me draw the peaks in opposite directions
m still not sure y they were post to be in the same directions but many of my friends said that it was the gradient which had to be considered
Idk but over there values of B are GREATER THAN Zero only. There arent any -ve values as were in our paperhttp://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-5.html read the explanation for Q34ii. it says"that since the gradient is in opposite directions emf would be in opposite direction to but in paper the gradient was in same direction
If we consider sign of B and put it in formula that we used before to prove the voltage wont we get a negative value of voltage?ik thaz wut made me draw the peaks in opposite directions
m still not sure y they were post to be in the same directions but many of my friends said that it was the gradient which had to be considered
no m not sure but idk they might be rightIf we consider sign of B and put it in formula that we used before to prove the voltage wont we get a negative value of voltage?
Are u sure your friends did it the right way?
IN the application booklet it is the range of frequencies occupied by a waveform. It would be the difference in max and min frequencies.ok m a lil worried now
wut was the definition of bandwidth? i wrote 'the maximum signal frequency carried by a carrier wave x 2' is that right?
and like i dint mention the 'no increase in kinetic energy 'during melting...i just wrote abt increase in potential energy of particles
do u think there will be a mark for Ek as well?
DAMN :/ M LOSING 6 MARKS ALREADYIN the application booklet it is the range of frequencies occupied by a waveform. It would be the difference in max and min frequencies.
As for the other you might lose a mark for not explaining why there was no temp change
The change could be say, 0-12= -12 or 0-(-12)=12 so change could be either -ve and +ve. no?no m not sure but idk they might be right
cuz the B was decreasing
it's not the value of B that matters but the change in B that does i think
lol idk manThe change could be say, 0-12= -12 or 0-(-12)=12 so change could be either -ve and +ve. no?
dude compare it to last yeai really hope the threshold stays between 55-60 or max of 62.
I think there wasnt much differemce although I made a few silly mistakes. What about you?lol idk man
u might be right
m not sure now but i drew the same graph n everybodys been telling me its wrong
dude just asking...did u find this year's paper tougher than last year's?
i found this one tougher :/I think there wasnt much differemce although I made a few silly mistakes. What about you?
dude idk i found this one tougher and like idk it should go below 55 now >.<i did 17 one a day before and got around 84, i think it was tougher than this year. NOOOOO last year was 55
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