- Messages
- 150
- Reaction score
- 222
- Points
- 53
Q10 20 22 24 26 29 31 37 39 ?? PLEASE EXPLAIN!!
http://papers.gceguide.com/A Levels/Physics (9702)/9702_w16_qp_12.pdf
q.29
the distance between two adjacent antinodes(maxima) in a stationary wave is 1/2 lamda, so 1 lambda is 1.5cm * 2= 3cm= 0.03m
f=v/lamda (wave equation)
v= 3.00*10^8 (given in first pg of exam paper) (microwave is light)
3.00*10^8 / 0.03 = 1*10^10 which is C