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When it's on the floor horizontally:Can someone please solve this
any help is much appreciated.
When making calculations based on values of gradients, make sure you use the REAL values (ie the one with powers of ten multiplied)I need help with finding the gradient of the lines in P5
These are the two papers
http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s12_qp_51.pdf
http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s10_qp_51.pdf
Please look at question 2 of both papers.
In the first link (s12 paper) to find the gradient I did,
(0.82-0.36)/(1.95-1.67)x10ˉ²
This gives 164
But the answer is 1.64 so my teacher said don't multiply by 10ˉ² since the graph says I/10ˉ²
In the second paper (s10) to find the gradient I did what my teacher said above
(334-152)/(4.5-2)
This gives 68.8
Now in part d, the answer should be 10^-6 whereas I get 10^-3
So in this case I had to multiply the
(334-152)/(4.5-2)x10^-3
to get the correct answer
So I am confused when to multiple by the power given on the axis and when not to? :/
Please help!
That's what i thought as well like always take the powersWhen making calculations based on values of gradients, make sure you use the REAL values (ie the one with powers of ten multiplied)
When asked to calculate the gradient of a graph, I'd prefer to use the real value still, but it seems they want without power of ten adjustments.
Unlikely to do with logs. It's simple scales. Powers of ten simply prevent having to like long decimals like 0.0035That's what i thought as well like always take the powers
but then in the first paper they're not using the power... is it something to do with logs?
Use centre of gravityHi everyone, can anyone please solve my Physics AS doubt?
Question 15 of the May June 2015 qp 12
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s15_qp_12.pdf
viscosity is not in the syllabus, download the syllabus from the cie guide and read what u wantRe: Physics Help here! Stuck somewhere?? Ask here!
Can anyone tell me what should i learn for pressure in lquids for As level and please give me the detailed explanation of viscosity in liquids asap !!! thanks
View attachment 57071
Why is q negative for the first row?
no thermal energy is supplied to the system since it's constant temperature right so then why zero??
Thankyou! And better late than never I had actually almost forgotten about this question and hadn't found an answerSorry for late reply you might have already got the answer but just in case I'll explain it.
For an ideal gas, Internal energy is proportional to Temperatuer.
Since temp= constant, Change in U=0
According to first law of thermodynamics, Q-W=0
Therefore, Q=W
Meaning all the heat added to the system is used to do work( thats why the -ve sign at q and +ve sign at w)
I use the least sf value given in the question.how many s.f should my answers be in paper 2? i always see 2 s.f in final answer and i use 3
how many s.f should my answers be in paper 2? i always see 2 s.f in final answer and i use 3
even if 1?I use the least sf value given in the question.
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