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Can you plz mark the places where it will be changed to ketone?oh i think i realised ur mistake ... u are counting both Carbon atoms in two of the C=C double bond ... i don't think we should do that ...
Thanks alot i got itIE naturally increases across the period because the nuclear charge is higher, so Mg wil lhavve more IE than Na. It will also have more IE than Al, because Al has an electron in the outer p shell which has more energy and is also farther than the nucleus. (Mg outer shell => 3s2, Al outer shell => 3s2 3p1)
Thank youActually, the most straightforward way to tackle this question is to refer to the list of IE and ionic radii in the data booklet as suggested by the question, and see which option fits the description.
HCl have very high difference of electronegetivity b/w them than other molecules... hence it has intermolecular force.... which diviates it from ideal gas the most.
One will be But-1-ene,and the other will be But-2-ene which will show cis-trans isomerism at the double bond.View attachment 54850
How will A give 3 alkenes? I can only find 2 ... :/
6A*student credits.View attachment 54847
Why D?
Isn't it
Mg = 0.5mol O2
Al = 0.75mol O2
S = 1mol O2 (since SO2 is formed right as SO3 required a catalyst)??
Actually, the most straightforward way to tackle this question is to refer to the list of IE and ionic radii in the data booklet as suggested by the question, and see which option fits the description.
Dayum xD Some questions they want you to take in account the catalyst... others they dont :S6A*student credits.
This is oxidation reactions forming oxides
eg. 1 Mg + 0.5O2 -> 1MgO
1 Al + 0.75O2 -> 0.5Al2O3
1 S + 1O2 -> 1 SO2 because its in excess oxygen 1SO2 + 0.5 O2 -> 1SO3 so overall equation is 1S + 1.5O2 -> 1SO3
the oxidation ratio is 0.5:0.75: 1.5 = 2:3:6 = 1:1.5:3 so answer is D
Can you plz mark the places where it will be changed to ketone?
I get 6.36 too :/Aoa, can someone help plz
View attachment 54849
Why C? Why is it bad if ammonia is given off?
(65 x 3 + 63 x 7) / 10 you divide by the total abundance, not 100Aoa, can someone help plz
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