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Physics, Chemistry and Biology: Post your doubts here!

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need help guys!! 0620/33/m/j/14...question 3(b) Kindly explain!! not able to upload the pikcha!! :(
 
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Could anyone explain me this?

Which of these pairs of aqueous ions BOTH react with dilute sulfuric acid to give a visible result?
A. Ba2+ and Cl-
B. Ba2+ and CO3 2-
C.NH4 + and Cl -
D. NH4+ and CO3 2-
 
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need help guys!! 0620/33/m/j/14...question 3(b) Kindly explain!! not able to upload the pikcha!! :(
I do think that the polymer is in the form of starch so it can be represented like this.Untitled.jpg
 

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how do we describe
1. the formation of ethanoic acid using acidified KMnO4 (3)
2.the usefulness of chromatography in separating and identifying mixtures(4)
Acidified potassium mangnate is an oxidising agent so just say that add potassium mangnate to ethanol inorder to form ethanoic acid
The usefulness of chromotography just means that u should know that it is used in identifying the colourless substances present in the mixtures by spraying the locating agent onto the chromotogram
 
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Could anyone explain me this?

Which of these pairs of aqueous ions BOTH react with dilute sulfuric acid to give a visible result?
A. Ba2+ and Cl-
B. Ba2+ and CO3 2-
C.NH4 + and Cl -
D. NH4+ and CO3 2-
The answer is B.
Cuz sulfuric acid has 2 ions H+ & SO4-
SO4- will react with Ba2+ to form BaSO4 which can be seen as a white precipitate
And plus any acid with any carbonate gives off carbon dioxide which can be seen as bubbles are formed!
 
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The answer is B.
Cuz sulfuric acid has 2 ions H+ & SO4-
SO4- will react with Ba2+ to form BaSO4 which can be seen as a white precipitate
And plus any acid with any carbonate gives off carbon dioxide which can be seen as bubbles are formed!

Thanks!
 
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112
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Acidified potassium mangnate is an oxidising agent so just say that add potassium mangnate to ethanol inorder to form ethanoic acid
The usefulness of chromotography just means that u should know that it is used in identifying the colourless substances present in the mixtures by spraying the locating agent onto the chromotogram
how about the equation.........
 
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