"
using proportional dilution, by adding a unit volume of a solution of a known concentration to a
solvent to obtain the required concentration, e.g. to dilute a stock solution by 5, 1 cm3 of the stock
solution is added to 4 cm3 of solvent. This gives a 1:5 dilution. To make a standard volume of a specific
concentration a formula V1C1 = V2C2 can be used. V1 is the volume of the stock solution, C1 the
concentration of the stock solution and V2 is the volume of the required solution, C2 is the concentration
of the required solution, e.g. a stock solution contains 100 mg cm–3 (C1) and need to make 10 cm3
(V2) of a solution with a concentration of 25 mg cm–3 (C2). The volume of stock solution needed is
V1 = 10 cm3 (V2) × 25 mg cm–3 (C2) / 100 mg cm–3 (C1). Cancelling units, V1 = 100 cm3 (V2) × 25 (C2) / 100
(C1) = 2.5 cm3"
I found this in our Biology syllabus. But I need more information about it.
using proportional dilution, by adding a unit volume of a solution of a known concentration to a
solvent to obtain the required concentration, e.g. to dilute a stock solution by 5, 1 cm3 of the stock
solution is added to 4 cm3 of solvent. This gives a 1:5 dilution. To make a standard volume of a specific
concentration a formula V1C1 = V2C2 can be used. V1 is the volume of the stock solution, C1 the
concentration of the stock solution and V2 is the volume of the required solution, C2 is the concentration
of the required solution, e.g. a stock solution contains 100 mg cm–3 (C1) and need to make 10 cm3
(V2) of a solution with a concentration of 25 mg cm–3 (C2). The volume of stock solution needed is
V1 = 10 cm3 (V2) × 25 mg cm–3 (C2) / 100 mg cm–3 (C1). Cancelling units, V1 = 100 cm3 (V2) × 25 (C2) / 100
(C1) = 2.5 cm3"
I found this in our Biology syllabus. But I need more information about it.
