Physics: Post your doubts here!

[crazytaylorfanXD]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s11_qp_12.pdf

Q 32 , ,33

 

[ashcull14]

hey where am i going wrong?
i did it like this:- net emf=3-1.2=1.8V
V1=9/27*1.8=0.6V
0.6/9=0.067...y is my ans wrong?

 

[ashcull14]

i thin

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_qp_12.pdf

Q 32 , ,33

k in q32...as l is doubled the cross sec area will be halved as well as it is an elastic material so R=2*2=4

 

[Thought blocker]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_qp_12.pdf

Q 32 , ,33

32)
V = P / I = C

33)

i thin

k in q32...as l is doubled the cross sec area will be halved as well as it is an elastic material so R=2*2=4

 

[Thought blocker]

View attachment 45251 hey where am i going wrong?
i did it like this:- net emf=3-1.2=1.8V
V1=9/27*1.8=0.6V
0.6/9=0.067...y is my ans wrong?

Question ?

 

[abdulrahmanmirxa]

thnk

18)
power output P=IV
23 x 320 =7360 W
power input Power=energy/time
so P=mgh/t
and m/t is= 200 kgs-1
so 200 x 9.81 x 8 =15696 W
output/input x 100
7360/15696=0.468
nd 0.498 x 1ooo =46.8
so answer is D

thnx

 

[Student12]

Question 3, 4 , 5 , 8 , 11 , 14 , 15 , 19 , 24 , 33 , 35 , 37 , 38 PLEASEEEE!http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w13_qp_12.pdf

Thought blocker

 

[Thought blocker]

Thought blocker

Please now I want to do my preparation... I'll solve it at night...
IF ANYONE CAN HELP HER!!!
I AM BUSY NOW IN MY SCHEDULE !

 

[ashcull14]

Question ?

attatchment 4251

 

[Thought blocker]

View attachment 45251 hey where am i going wrong?
i did it like this:- net emf=3-1.2=1.8V
V1=9/27*1.8=0.6V
0.6/9=0.067...y is my ans wrong?

0.2 ?

 

[ashcull14]

0.2 ?

.YEA//HW?

 

[Thought blocker]

.YEA//HW?

Here Resistors are connected in parallel, so there will be different currents in the circuit...
we are asked for the 9Ω resistor
so I = V/R
I = (3-1.2) / 9 = 0.2A

 

[ashcull14]

Here Resistors are connected in parallel, so there will be different currents in the circuit...
we are asked for the 9Ω resistor
so I = V/R
I = (3-1.2) / 9 = 0.2A

thnks ...(silly me..:s)

 

[Thought blocker]

thnks ...(silly me..:s)

Help Student12 Please.

 

[Student12]

Help Student12 Please.

Do some of them at least or by tonight.. :/ i know you have to prepare.

 

[chymera]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w12_qp_13.pdf

question 21


thought blocker????

 

[ashcull14]

 

[Mohammad Farzanullah]

plz explain the scenario at Y. i cant figure it out

 

[Thought blocker]

Do some of them at least or by tonight.. :/ i know you have to prepare.

yeah will do it tonight

 

[Thought blocker]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w12_qp_13.pdf

question 21


thought blocker????

LAST ANSWER NOW!!! BYE