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Chemistry: Post your doubts here!

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This stuff isn't in the syllabus or taught. This is precisely why it has shown you the 4 figures above the actual question. The examiner wants you to analyze those figures, see whats going on, and apply THAT to the question.

The question shows that all carbons in Benzene can be made to lie on the same plane, but not in cyclohexane. The question also shows that butane Carbons can be made to lie on the same plane, but methylpropane, also an alkane, cannot.
This tells us that if a compound has a ring, OR branching, it cannot be made to lie on the same plane.

All of them are co-planer apart from B.

C is coplaner because you don't have to consider the Oxygen atoms. The others are unbranched and two individual chains lying on the same plane.
 
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I know its because of the size.But why? :/
Well i guess its cause Cl^- is smaller than I^-
So fitting 7 atoms of F around a Cl atom is difficult due to a lot of repulsion between the electrons.
But cause an I atom is bigger it can attach to 7 F atoms easily :)
this would make more sense
you know that electrons repel so more the place the have future away they will be and more the stable than being in tiny place
think of a lot of people in a car they would argue to get 1 full seat and no one to sit next to them but if you have a bigger car more places to sit....this is just an example
 
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this would make more sense
you know that electrons repel so more the place the have future away they will be and more the stable than being in tiny place
think of a lot of people in a car they would argue to get 1 full seat and no one to sit next to them but if you have a bigger car more places to sit....this is just an example
okay.I see some things in chemistry are not very logic based :p
 
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a free radical has one unpaired valence electron which gives it high reactivity.
to make CaSO4 from Ca(NO3)2, you will need a soluble (otherwise no reaction will occur as the salt will not dissolve) salt that has a metal(X) cation that can displace Ca to form XNO3 and a sulfate anion to replace NO3
Sodium Sulphate would do the job.
again the same kind of question. any soluble sulfate salt would do the job. sodium sulfate is, i am sure, soluble.
we have studied in hydroxy compounds chapter that -OH can be replaced by a halogen with help of PCl3 or PCL5 or red phosphorus+halogen(I2, Br2 etc) + acid + heat
that will replace OH group.
CH3(CH2)4CH(Cl)CH=CHCHO
 
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how much marks do we need to score to get an A in Chem P1 and P2?
As sitoon said:
P1 > 32-34 mostly
P2 > 48 &above
But it also depends on number of other factors. Especially the marks curve or such in your area. If many people didn't score high marks or most of them have low marks then the curve will go down, i.e. you might need less marks to score an A in p1 it might be 25 or more.
Curse is like some sort of chart depending on your grade and all other candidates in your area grades/marks. If the average mark per candidate is low then the, marks for getting A will become low. If they are high, then for getting A you might need higher marks. ;)
 
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As sitoon said:
P1 > 32-34 mostly
P2 > 48 &above
But it also depends on number of other factors. Especially the marks curve or such in your area. If many people didn't score high marks or most of them have low marks then the curve will go down, i.e. you might need less marks to score an A in p1 it might be 25 or more.
Curse is like some sort of chart depending on your grade and all other candidates in your area grades/marks. If the average mark per candidate is low then the, marks for getting A will become low. If they are high, then for getting A you might need higher marks. ;)

According to the trend table I've drawn up on Excel from last year (updated it right now though), the average P1 A in the last 4 years is at 28.5 raw marks with a standard deviation of 2.03 while the average A in P2 in the same time is 44.8 with a standard deviation of 2.5. Both of which are easily achievable if you're thorough with your concepts btw.
 
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Can someone explain Q6f(ii) & (iii)? (My doubt is actually iii, so work on that one first, I just want to make sure if my reasoning behind ii is correct)

Thank you!
Yo,.I think i can explain u this.Its a shape that u have to imagine.
K to do this u have to imagine the struc.Its a bit hard to explain i will try my best.
The drawing i drew is how the bond lines look when they r rotated around.Thats why j is selcted.SEE the right hand pattern .....
The idea for the last part is u need to find smthg that is totally diff than all others but as u know rotation must be on the same plane.
For f n g the right part had showed all possibilities with such arrangement so u must take h as an example for right hand side.Now to sort the left side,u need tomake sure its diff than h.So u will get a new isomer.Hope u understand......
 

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Describe and explain how the solubility of magnesium sulfate compares to that of barium sulfate? Anyone please ! [4 points]
 
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Describe and explain how the solubility of magnesium sulfate compares to that of barium sulfate? Anyone please ! [4 points]
Hey I have this question and answer. You can adjust your answer accordingly:

Q. Describe and explain the trend in the solubility of the sulfates of the group II elements.

Ans.
- Solubility decreases (down group II) [1]
- lattice energy decreases [1]
- solvation/hydration energy (of cation) decreases [1]
- but more so than lattice energy / is not able to overcome LE [1]
- (delta)Hsoln becomes more endothermic / positive / less exothermic [1]

[max 4]
 
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Yo,.I think i can explain u this.Its a shape that u have to imagine.
K to do this u have to imagine the struc.Its a bit hard to explain i will try my best.
The drawing i drew is how the bond lines look when they r rotated around.Thats why j is selcted.SEE the right hand pattern .....
The idea for the last part is u need to find smthg that is totally diff than all others but as u know rotation must be on the same plane.
For f n g the right part had showed all possibilities with such arrangement so u must take h as an example for right hand side.Now to sort the left side,u need tomake sure its diff than h.So u will get a new isomer.Hope u understand......

Nah don´t get it :D I seem to get part iii, but now I dont understand what u mean with part ii. :(
 
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