Physics: Post your doubts here!

[usama321]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s10_qp_22.pdf
Someone "Q6(d)", please

CB also has resistance. So there is some voltage across it too. The rest of the voltage is then equally dissipated across the two parallel wires

 

[NinjaInPyjamas]

okay so it is very simple:
difference in pressure = rho g (difference on height)
difference in height= 6
only D and C had difference of 6
the height of column attached to high pressure will have smaller height.
so D is answer.

ok, so it really simple! thanks!

 

[Snow Angel]

thank u very much but i dont think i asked abt the current question. the actual question is question 6b) from :
papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w07_qp_2.pdf

thanks in advance. Suchal Riaz

 

[Thought blocker]

thank u very much but i dont think i asked abt the current question. the actual question is question 6b) from :
papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w07_qp_2.pdf

thanks in advance. Suchal Riaz

Sure :
5a)
its easier if u convert the angle in radian ie multiply by (π/180°) ----> 60° = π/3 rads.
n c this --->
thts whr the new wave will start!

So it would look like :

Correct me if it is wrong. ZaqZainab Suchal Riaz

 

[Snow Angel]

View attachment 39458

thank u very much but i dont think i asked abt the current question. the actual question is question 6b) from :
papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w07_qp_2.pdf

thanks in advance. Suchal Riaz

 

[biscuitbiscuit]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w10_qp_21.pdf
"Q6(ii) " sketch would be appreciated

 

[Thought blocker]

thank u very much but i dont think i asked abt the current question. the actual question is question 6b) from :
papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w07_qp_2.pdf

thanks in advance. Suchal Riaz

bi)
V= 230 -225 = 5
R=V/I =0.11ohm

bii)rho = 1.8*10^-8,Length = 16, Resistance = 0.11
R=rho*L/A
0.11=(1.8*10^-8*32)/A
A=5.3*10^-6 m^2

 

[Thought blocker]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w10_qp_21.pdf
"Q6(ii) " sketch would be appreciated

Not sure. Suchal Riaz ZaqZainab usama321
Well is a st line till 3A and 12 V and then curve.

 

[usama321]

Not sure. Suchal Riaz ZaqZainab usama321
Well is a st line till 3A and 12 V and then curve.View attachment 39465

Straight line at start, and then curves downwards... but NEVER horizontal

 

[sara kamal]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_qp_41.pdf @ ninjaln Pyjamas,usama321,biscuitbiscuit,Mohammmed salik

please explain Q10 c 2
and Q9 b2

 

[Suchal Riaz]

Not sure. Suchal Riaz ZaqZainab usama321
Well is a st line till 3A and 12 V and then curve.View attachment 39465

 

[Thought blocker]

Sure :
5a)
its easier if u convert the angle in radian ie multiply by (π/180°) ----> 60° = π/3 rads.
n c this --->
thts whr the new wave will start!

So it would look like :

Correct me if it is wrong. ZaqZainab Suchal Riaz

Suchal Riaz is this correct ?

 

[biscuitbiscuit]

Straight line at start, and then curves downwards... but NEVER horizontal

Hey can you please explain Q6(c) also

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w10_qp_22.pdf

 

[biscuitbiscuit]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_qp_41.pdf @ ninjaln Pyjamas,usama321,biscuitbiscuit,Mohammmed salik

please explain Q10 c 2
and Q9 b2

Still in As, maybe next year

 

[Fahm Deen]

Oct/Nov 2010/21 Question-6.b . Please give me a solution with complete explanation.

 

[sitooon]

MS :
force on mass = mg (where g is the acceleration of free fall
/gravitational field strength)
g = GM/r^2
if r @ h, g is constant
ΔEP = force × distance moved
= mgh

 

[chocolate_girl]

16:
B is incorrect because the velocity does not decrease uniformly (it's roughly parabolic), which means height of the ball does not increase uniformly, which means the potential energy of the ball does not increase uniformly (since Ep = mgh and rate of h is not constant).
26:
HOPE IT HELPS

Emm i dont find any explanation for 26 but thanks for helping with 16

 

[Suchal Riaz]

Emm i dont find any explanation for 26 but thanks for helping with 16

-->Intensity is directly propotional to square of a
it means if A in two times, I is four times
-->Intensity is inversely proportional to area
by first rule and second rule, E increase 4 times due to doubling of A but decreases 1/2 times due to halving of area. so E(new) = E*4/2=2E

 

[Suchal Riaz]

View attachment 39472

MS :
force on mass = mg (where g is the acceleration of free fall
/gravitational field strength)
g = GM/r^2
if r @ h, g is constant
ΔEP = force × distance moved
= mgh

change in U = Work done against weight
= F.s = W.h=m.g.h

 

[Suchal Riaz]

Hey can you please explain Q6(c) also

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w10_qp_22.pdf

okay so the range is from 1.5 to 3.5 V for 0-25 C
Volt meter reads only upto one decimal place, 0.1 V. 0.1V/1V * 25 C = 2.5 C. it means that the temperature can be known close to 2.5 C of the real values.
and secondly the circuit has another problem. the line is not straight. so same change for temperature is not same change for voltage for all values. it changes.