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http://papers.xtremepapers.com/CIE/... AS Level/Chemistry (9701)/9701_w10_qp_12.pdf
please explain Q3,7,8,27,34,38.
thanks in advance!
please explain Q3,7,8,27,34,38.
thanks in advance!
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The answer should be B.
D is showing the overlap of four orbitals, and is hence showing a square-planer arrangement. (Hint hint: XeF4). We all know that XeF4 contains 4 sigma bonds, regardless of what the diagram is showing. Hence, D is not the correct answer, rather a smartly made confusing option.
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_s08_qp_1.pdf
guys , i need help with Q2 and 27.. thnx a lot !!!!
question 10
please answer this questionnss pleaseee
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w05_qp_1.pdf question31
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w03_qp_1.pdf question 2,23 and 31
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_s04_qp_1.pdf question 9 and 18
and the last question is http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w05_qp_1.pdf question 7
pleasee atleast answer what u know
question 2 10cm3 of cs2 and 30cm3 of 3o2 ,they r equal to the number of moles ,and 10cm3 of co2,and 20 of so2
then they said 50 cm3 of oxygen but only 30 reacted so 20 are left ,this 20cm3 of oxygen left u add them with 10cm3 and 20cm3 of co2 and so2 so u get 50 sm3 of gas after burning
and for the volume of gas after adding naoh im not sure but i guess because of when naoh rects with the products it gives 2NAOH +SO2+CO2+NA2CO3+H2CO3 SO2 and so2 and co2 reacts so 20 is left from naoh
question 30
number of moles of ethanol is 0.65 and for ethanoic acid is 0.5
and the mass for ch3co2ch2ch3 is 0.5*82=44
they want the yield of ester so the mass of ethanoic acid 22/44*100
Answer is C. If 2 can be correct, why not 1?
neither do I , I chose B , because I thought that it shows the correct shape of a p orbital which is a dumbbell shape , don't you agree?i dont get it
Can anyone please explain the following question?
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_s04_qp_1.pdf Q:28
Answer is C. If 2 can be correct, why not 1?
question 9 , I don't know any one help??.. question 19 it's A right? draw the displayed formula of the compounds and try to make a chiral center from the elements given to you, if you can't then it won't form an optical isomer , like in iv there's also a double bond and the only carbon with a single bond must have either two hydrogen's or two bromine get ?..in 28 it's C right? if you draw the displayed formula of the compound u will see that the double bond is still there , that's because nabh4 will only reduce the aldehyde group to it's primary alcohol , the other options are insensible because for example in A addition of hydrogen in that method will not reduce the aldehyde , it will only make the double bond single. hope you understood
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