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Thnku*girl and a boy sorry for thatno problemo butt ummm *ahem ahem not a boy ahe ahem*
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Thnku*girl and a boy sorry for thatno problemo butt ummm *ahem ahem not a boy ahe ahem*
no u got that wrong..... see that x is in both the values 2x and 1/x also ..... now do ithttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s03_qp_1.pdf
Ok so in question 1, the markscheme says they take the 4th term, why? (1/x) comes when 5C1 ryt, thats where there comes (1/x) so why the 4th term?!
since g(x) = x-2can you tell me how to make Q7 iii pls
for these type of equations use this formulaehttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s03_qp_1.pdf
Ok so in question 1, the markscheme says they take the 4th term, why? (1/x) comes when 5C1 ryt, thats where there comes (1/x) so why the 4th term?!
NO... so u didn't get what I saidyeah but in (ii) It's asking about a different equation , not the one i already sketched. and it's for one mark , do i have to sketch that as well?
thanks al
Thanks alot many thanks but can u just tell me when is it necessary for us to double derivate it and put it equal to zero ?
double derivate was not required in this question .... actually double derivate is just used to tell the nature the of the function ... however i wanted minimum vale dy/dx ... take it this way
you have to find minimum value of the function f(x) = 3x^2 -8x +4
You can find it in two ways either express it in (x-h)^2 +k form where k will be the minimum value
or
just derivate the function and equate it to zero to get the x-cordinate of the minimum point .. and then insert that value of x in the minimum value of the function..
it just happend to be that f(x) that we are talking about was dy/dx ... so derivative of that function was double derivative ..
Hope i m clear..
i posted this before as well
u got me there.. XDNature of the stationary point*.
i posted this before as well
triangle is just used for sin xHonestly I don't get it fully.
I get that tanx = ab/bc (duh! )
But further.. not really.
triangle is just used for sin x
AC is calculated by pythagoras theorem
first two part, i recommend yu learn it tan(pi-x) = -tanx and tan(0.5pi-x) = 1/tanx
if yu want to know how ... i would be happy to tell you.. there logic lies in tan graph...
ur guess is ryt .. just to be confidence yu can practically try it ...I think I understand tan(pi-x) = -tanx in relation to the graph...
Is it because every pi units the graph is upside down, like at tan(x) it would be going up and at tan(pi-x) it would be going down. Just a logical guess.
Wow really?ur guess is ryt .. just to be confidence yu can practically try it ...
Wow really?
Too bad I can't make such conclusions in an exam, I get so tense.
its chem bro..p1 any one plz solve question 8 part 3
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