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Oh alright....
To calculate the con of succinate in water layer: Moles of NaOH=Moles of Succinate this is wrong. because 2 moles of NaOH reacts with 1 mole of the acid because the acid has 2 carboxylic groups not one. its so hard to find a scale for that graph..Oh alright....
Succinate acid is being dissolved in the water and ether:
The 10 cm3 water layer contains succinate
the 25 cm3 ether layer also contains succinate.
(we take these two as the volume of succinate that is being reacted with NaOH)
To calculate the con of succinate in water layer: Moles of NaOH=Moles of Succinate
Moles of NaOH= B/1000 x 0.1 = 0.1B/1000
Moles of Succiante= 10/1000 x D = 10D/1000
to find column D: (0.1B/1000) / (10/1000) =0.01B
The same method applies to find the concentration of succinate in ether layer
Plot the graph, and you get the line of best fit passing through the origin
Hope i helped you guys!
Don't worry, it'll happen. Keep faith in Allah and pray a lot, there're still 10 days 15 days to p4, revise only the group chemistry and the organic of AS, not the whole syll really. InshAllah, we'll pass
Yeah, you have a point... hmm.. alright then, try the method i told you with 2moles instead of 1.. I'll try as well; if i get the scale, i'll let you know inshAllah.
thank you so much if you are able to get a perfect scale and a good graph please do upload a picture of it, if it is okYeah, you have a point... hmm.. alright then, try the method i told you with 2moles instead of 1.. I'll try as well; if i get the scale, i'll let you know inshAllah.
Thanks a lot for telling me though
Jazak Allahu Khair
Btw, read the whole mark scheme, i dont think the number of moles really matters cuz we'll just get smalller values. the marking scheme just wants the line passing through the origin, and its not really stating the method of finding the concentration. later on in the paper, we have to find the gradient of our line: My gradient according to the method i told u is 0.062- what i dont understand abou the marking scheme is that it says, "...must be in the order of 16.3/0.062". and further on: "yes, since the results produce a good linear/straight line graph, the procedure is OK".
did u read the examiner report of this question ?
OH NO!!! I think it does matter! Read the examiner's report on this question. column D's heading must be 0.1B/20 based on the 2:1 mole ratio principle!thank you so much if you are able to get a perfect scale and a good graph please do upload a picture of it, if it is ok
just did
we should....
The examiner's report also tells what scale we can use ... u put me in a hassle
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