Mathematics: Post your doubts here!

[mominzahid]

wen we square a line and integrate fr given limits it gives us the volume under that p[articular line or curve
wen there is no line given and its a straight line parralel to x axis the eq of line wud be y=2

now see volume under y=2 gives us the complete vol under line ie the whole rectangle
no we dun need the non shaded region of the rectangle
non shaded region of rectangle = vol under the curve

now u kno
vol of shaded + vol of non shaded = vol of total rectangle
so vol of shaded = total (under y=2) - non shaded (under curve)
ask again if u dun get it

Hey... THANKS ALOTT..
I was stuck at this stupid question for over an hour and turns out it was the simplest thing.
Thanks alot again

 

[mominzahid]

y=2 is the equation of the straight line
the area under the shaded region = area under line - area under graph

that is why we had to subtract the two integrals

I got it.. Thanks alott..
Really Appreciate it

 

[nafis shahRiyar]

http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20(9709)/9709_w12_qp_12.pdf

i dont understand question 11 :| can someone explain?

 

[PANDA-]

I hope not.. the 2012 papers were extremely difficult!

Same, the 2012 papers were just wrong. I hope they make it easy

 

[syed1995]

Same, the 2012 papers were just wrong. I hope they make it easy

And the threshold wasn't any lower either!

 

[abruzzi]

plot g(x) and then reflect it in x=y line in order to get g(x^-1)

Yeah.. but how do I get the y-intercept and x-intercept??

 

[PANDA-]

And the threshold wasn't any lower either!

How much do you get on average when solving P1? As in past papers.

 

[nafis shahRiyar]

Yeah.. but how do I get the y-intercept and x-intercept??

you dont have any intercept in this graph,look carefully the range is given from k<x<4 and where you found k=2
so,when x is 2,y is 8
when x is 3,y is 7 and when x is 4,y is 4.
plot them and join the curve

 

[daredevil]

I got it.. Thanks alott..
Really Appreciate it

np

 

[abruzzi]

you dont have any intercept in this graph,look carefully the range is given from k<x<4 and where you found k=2
so,when x is 2,y is 8
when x is 3,y is 7 and when x is 4,y is 4.
plot them and join the curve

Oh yeah.. thanks

 

[syed1995]

How much do you get on average when solving P1? As in past papers.

around 60 or so .. but the 2012 ones were quite a disaster .. one of them went for 48

 

[sma786]

http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_s04_qp_1.pdf
Question 4, (ii) , what is the basic rule for these types of questions?

 

[nafis shahRiyar]

Oh yeah.. thanks

anytime

 

[MustafaMotani]

j

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s04_qp_1.pdf
Question 4, (ii) , what is the basic rule for these types of questions?

just multiply those terms that give u your desired term (X^3) in this case ...
like in (1-3x)(1+2x)^6
multiply 1 by the term with x^3 in the expansion of (1+2x)^6 (prev part) and multiply -3x by the term with x^3 in the expansion of (1+2x)^6

 

[daredevil]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w12_qp_12.pdf

i dont understand question 11 :| can someone explain?

hey
I am solving ur question but hree's the deal. u need to have that paper and a page and pencil with u and u need to do it as I walk u through it otherwise u won't get it bcz making a diagram here won't be possible for mme and u hav to bear with the descriptions of the diagram nad make one for urself side by side.


see wat u need to do here is make a right angled triangle. consider OR to be the tangent and make a radius line from C to R. connect C to O also..... there u have ur right angle.

in part i) Sin(thita) = x/20
thita = 1.2/2 = 0.6 radians

solve it and u will get 7.218cm

in part ii) Area = (Area of sector) - (Area of circle)
= [(1/2)(1.2)(20)^2] - [(pie)(7.218)^2]
= 240 - 163.68
= 76.32 cm^2

got it??

 

[daredevil]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s04_qp_1.pdf
Question 4, (ii) , what is the basic rule for these types of questions?

adding to what Mustafa said.... actually just emphasising a point he already made.... use the expanded form instead of the secnd bracket.... meaning the answer of ur 1st part it makes the questions a lot less confusing and it becomes vivid as to wat u need to do there

 

[MustafaMotani]

adding to what Mustafa said.... actually just emphasising a point he already made.... use the expanded form instead of the secnd bracket.... meaning the answer of ur 1st part it makes the questions a lot less confusing and it becomes vivid as to wat u need to do there

she doesnt need to expand in first part.. -.-

 

[Rutzaba]

around 60 or so .. but the 2012 ones were quite a disaster .. one of them went for 48

out of 75? :O

 

[daredevil]

she doesnt need to expand in first part.. -.-

ohh oops *sleep deprivation error* better go now starting to be a liability now

 

[abcde]

I hope I'm not late.

Here: http://www.mediafire.com/?6hwfccjmuht9cah

Thank you. :]