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Can someone pleasee explain me the the following paper 1 questions
o/n 05 Q1
m/j 05 Q1 & 2
o/n 04 Q3
m/j 04 Q3
o/n 03 Q1
:/
o/n 05 Q1
m/j 05 Q1 & 2
o/n 04 Q3
m/j 04 Q3
o/n 03 Q1
:/
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would you please solve
38 A number of alcohols with the formula C4H10O are separately oxidised. Using 70g of the alcohols
a 62% yield of organic product is achieved.
What mass of product could be obtained?
1 42.2g of butanone
2 51.6g of butanoic acid
3 51.6g of 2-methyl propanoic acid
HERE IS TH MS JUNE 2002 P2can u please post the marking scheme of june 2002 chem theory paper
AlCl3 ... its that concept about the charge density of Al being too high that it attains a covalent character by attracting the electrons more towards itself.... if u don't get it them reply and i'll explain in detailCAN SOME View attachment 22063 SOLVE THESE
what is the answer given in the ms?PLEAView attachment 22064 SE SOLVE
refer to the organic reactions and see the HBr reactions, you'll find one that makes that benzene ring thing in option 1 and of course the halogenoalkane from option 2 .... option 3 however will not be selected because the H in the OH group is not replaced when a reaction happens, this whole group either goes or it doesn't change.... i hope i got it right.Can someone also please clarify May/June 2006 paper1 question number 38? Thanks in advance.
i odn't get these answers either... tag me to the answers wen u get them?? ^_^I need help. I can't understand these two MCQs. i) Which of the enthalpy changes of the following reactions can only be obtained by Hess's law. 1 The hydration of anhydrous copper sulphate to form crystals of CuSO4.5H2O 2. The formation of methane from its elements 3. The combustion of glucose, C6H12O6 ii) Sodium ions can be formed from sodium atoms. Na(s) ---> Na+(g) Which quantities are required to calculate the enthalpy change of formation of gaseous sodium ions? 1 enthalpy change of atomisation of sodium 2 first ionisation energy of sodium 3 enthalpy change of formation of sodium.
answer is C in mswhat is the answer given in the ms?
yeah thats what i thought.... CN has a triple bond.. that means all three of the N's valence electrons are bonded but 1 electron on C is remaining that is the cyanide ion... so 3 PAIRS of electrons are in bonding. other than that one pair in the s shell of each atom is unbonded. got it??answer is C in ms
I have no idea about the first question but I figured out the second one. In order for Na(s) to become Na+(g), two separate reactions has to take place. Reaction 1 : Na(s) --- Na(g) [enthalpy change of atomisation of Na] Reaction 2 : Na(g) --- Na+(g) [first ionisation energy of Na]. The enthalpy change of the reaction can hence be calculated by adding enthalpy change of atomisation of Na and the first ionisation energy of Na. The answer is therefore B (Option 1 and 2). As for option 3, enthalpy change of formation of any element is 0. So option 3 won't be considered. If anyone can figure out the first question, let me know!i odn't get these answers either... tag me to the answers wen u get them?? ^_^
In options 1 and 2, the products are formed by electrophilic addition of DBr and alkene. Option 3 is not possible because when DBr reacts with alcohol in a nucleophilic substitution reaction the hydrogen in the OH is not replaced by D. So the answer is option 1 and 2, right? Correct me if I am wrong. Thanks for your help.refer to the organic reactions and see the HBr reactions, you'll find one that makes that benzene ring thing in option 1 and of course the halogenoalkane from option 2 .... option 3 however will not be selected because the H in the OH group is not replaced when a reaction happens, this whole group either goes or it doesn't change.... i hope i got it right.
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