Physics: Post your doubts here!

[gary221]

can someone help me with these questions?

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s09_qp_1.pdf

10 20 25 and 29

10) conservation of momentum = momentum b4 and after are always equal.
So, since b4 the split, the momentum = 0...hence after the split the total momentum shud also =0 ----> the momentum if both the particles shud be the same (as they moce in opp direction,the momenta cancel each other out).
So, since one particle has mass = 2m, the other will have velocity = 2v.
So, the momentum wud be 2mv for both.

Now, for K.E. we square the velocity.
So, particle 1, mass = m. velocity = 2v. so K.E. = 1/2 * m * (2v)^2 ------> 2mv^2
particle 2, mass = 2m. velocity = v. so K.E. = 1/2 * 2m * v^2 -----> mv^2

ratio = 2: 1

Hope i helped.
All credit to Nibz

 

[papersxtreme]

june 2012/ 11 mcq 12

june 2012/12 mcq 13

Help. Please

 

[gary221]

can someone help me with these questions?

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s09_qp_1.pdf

10 20 25 and 29

25) formula for diffraction grating ----> nλ = dsinΘ
check this out ---->http://www.s-cool.co.uk/a-level/physics/diffraction/revise-it/diffraction-from-a-diffraction-grating
so d = 1/N, N = no of lines

So, the formula = nλ = sinΘ/N
gradient = sinΘ/λ
So, rearranging the abv formula, sinΘ/λ = Nn
Ans = C

Hope i helped.
All credit to Nibz

 

[messi10]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w10_qp_53.pdf

Oct/nov 2010 p53. Q no 1

Can anyone please provide assistance in Q 1.
How the diagram and little about procedure..

In mark scheme, its a bit confusing for me.

I'll be grateful.
Regards!

 

[gary221]

june 2012/ 11 mcq 12

june 2012/12 mcq 13

Help. Please

link?

 

[Tkp]

hey in n07 to measure pressure we are using pressure gauge. it's saying not allow pressure meter or barometer. so in calculating pressure do we always use pressure gauge or sometimes pressure meter or barometer can be used. and in mark scheme there is a pt written difficulty in measuring amplitudes at small pressures. Use a large incident source. So i wrote that use high values of p so that a could be measures easily. So can u explain this mark scheme point. And another point that the window should be perpendicular to source. Should we write this point whenever something is being transmitted through a substance? And what is the purpose of the pt. these are a lot of questions sorry but plzz help

Didnt understand what u said?give me a ques similar like this

 

[Ahmedraza73]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s11_qp_12.pdf
help me with the question no:9,15,17
Please anyone

 

[Ahmedraza73]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w09_qp_12.pdf
help me some with Q:8,9,12,26

 

[anishniroula]

can you guys help me to draw a
diagram for Specimen paper 5 q
no 1.
http://www.cie.org.uk/docs/
dynamic/19428.pdf

please post the diagram.

 

[zackle09]

for 22 apply the formula of Young modulus
FL/AX=E
SO WE Need to find the change in length
f=20,a=pie*(5*10^-4/2)^2
e=2*10^11
u will get 5*10^-4
and for percentage multiply by 100

i had the same question..im not getting 5*10^-4 :/
and they havent given us extenstion either

 

[zackle09]

25) formula for diffraction grating ----> nλ = dsinΘ
check this out ---->http://www.s-cool.co.uk/a-level/physics/diffraction/revise-it/diffraction-from-a-diffraction-grating
so d = 1/N, N = no of lines

So, the formula = nλ = sinΘ/N
gradient = sinΘ/λ
So, rearranging the abv formula, sinΘ/λ = Nn
Ans = C

Hope i helped.
All credit to Nibz

yeah i thought that too but the answers A :/

 

[gary221]

yeah i thought that too but the answers A :/

oh, sorry, i meant A..my bad...
the gradient =nN

Hope i helped.
All credit to Nibz

 

[TaffsAsLevel]

Any one understand the diagram for November 2010 paper 51? How do you draw it? It says coil Y is winded up tightly around coil X? How's that possible and mark scheme says there should be two independent coil labelled X and Y? Please help

 

[Farru]

Any one understand the diagram for November 2010 paper 51? How do you draw it? It says coil Y is winded up tightly around coil X? How's that possible and mark scheme says there should be two independent coil labelled X and Y? Please help

its a simple transformer :/

the pic I have uploaded shows the 2wires winded..
plus the bold wire shows wire y, and the other one is x..

if u gt ths diagram abt how they will wind up.lemme know, othrwse I will make the whole diagram..

 

[Farru]

its a simple transformer :/

the pic I have uploaded shows the 2wires winded..
plus the bold wire shows wire y, and the other one is x..

if u gt ths diagram abt how they will wind up.lemme know, othrwse I will make the whole diagram..

also the wires shuld not touch each other!

 

[Farru]

can you guys help me to draw a
diagram for Specimen paper 5 q
no 1.
http://www.cie.org.uk/docs/
dynamic/19428.pdf

please post the diagram.

please post which paper you are asking..

 

[raamish]

hey what is meant by the hall probe is in same orientation?

 

[raamish]

please post which paper you are asking..

what is meant by the hall probe is in same orientation?and in n11/51 is hall probe positioned on the centre of the flat coil?

 

[adibshamsuddin]

I need help in no. 12 and 15 of 9702_s12_qp_11.pdf. Help would be very much appreciated
http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s12_qp_11.pdf

 

[athaan]

I'd like a clear explanation about fission of nuclei. I can't seem to get it right.

(90 38) Sr -> (90 39)Y + (0 -1) e + 0.55MeV

why would it release energy if the binding energy of Y is greater than Sr? I'd understand if Sr has greater binding energy, but in fact it does not.
I'm trying to look for an answer that doesn't have to do with the binding per nucleon energy graph. Is binding energy negative or positive?