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Further Mathematics: Post your doubts here!

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It was a link not a pic. , I would really love to help you but i dont have notes its all in my head , just search the internet and i promise you will find answers to all your questions :)
If that's taking your time , try to give me a link !:cry:
 
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upload_2014-4-11_23-29-37.png

When section is removed in part ( ii ) , how do we find the area ?
Mark scheme ans :
(2/3 π x 0.6^3 x 3/8 x 0.6) – (π x 0.6^3 x 0.3) + (0.48A x 0.36) = 0, A = 3π /16.
shouldn't area be subtracted ? and why they equated with zero

iii > one mark but seems to be the toughest question:p ..any solution for it .
 
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View attachment 38846

When section is removed in part ( ii ) , how do we find the area ?
Mark scheme ans :
(2/3 π x 0.6^3 x 3/8 x 0.6) – (π x 0.6^3 x 0.3) + (0.48A x 0.36) = 0, A = 3π /16.
shouldn't area be subtracted ? and why they equated with zero

iii > one mark but seems to be the toughest question:p ..any solution for it .
this is how personaly i solved the question when i was doing AL
the last part mey be tricky to understand , but you can think of it of balancing a ruler on your finger then removing equal masses from both ends => center of mass is still where it is !
 

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Part (i) > No idea '
Part (ii) > just tell me what will be distance from centre of mass of triangle to AB &why

upload_2014-4-20_23-26-2.png
 
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