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I dont get it.
Perhaps you can explain why you think the equilibrium on the left cell would change if sulfates was added, using any equilibrium equations you think is relevant.
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I dont get it.
Which question are you referring to?Perhaps you can explain why you think the equilibrium on the left cell would change if sulfates was added, using any equilibrium equations you think is relevant.
Which question are you referring to?
I cant open this link.I'm referring to the reply by The Sarcastic Retard.
For your queries, you can click on the link on my signature "YouTube Videos for solutions to 9701 MCQ"
I cant open this link.
View attachment 58773
Part (ii)
hmm..this question was addressed here.
https://www.xtremepapers.com/commun...st-your-doubts-here.9859/page-733#post-942233
Thank you so much!order with respect to [CH3CHO] is 1
order with respect to [CH3OH] is 1
You would need answers to part a and b to find order with respect with H+, compare any two experiments and also sub in orders with respect to [CH3CHO] and [CH3OH].
e.g
Experiment 1 and 4
View attachment 58772
thank you very much!! And I will see to it that the stated details are included
You should learn these reactions
Because when dilute ammonia aqueous is used dropwise the NH3 not being a stronger base than the OH- cant take part in the reaction. As dilute ammonia aqueous means.
NH3 + 2 H2O -----> NH4+ + 2 OH-
The OH being the stronger one when dil NH3 is used in little amount reacts with Ni to displace Two aqua groups to form a complex [Ni(H2O)4(OH)2].
And as the Ni previously had a charge of +2 and OH is - and there are 2 OH thus the charge neutralises and the complex produced is neutral.
You should learn these reactions
They're in ligand exchange in transition elements
- example given in book is with Cu while here it is Ni but the overall reactions will be the same
thnx guys yeah i kinda new the reaction but didnt exactly know the reason
You got the reason now, right?
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