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Physics: Post your doubts here!

usama321

usama321

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Snackbox86 said:
Hey,I have a few MCQ AS physics questions i need help with
Q 14, 20
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w09_qp_12.pdf
Thank you
Click to expand...

Using conservation of momentum, the velocity of the 1kg trolley would be
2*2 = 1* x
x = 4 m/s

now total kinetic energy of the two trolleys would be equal to the total energy released from the spring

1/2 * 2 * 4 + 1/2 * 1 * 16
= 12 J

For the 20th one, the strain energy would be the area under the graph...
By just taking a triangle, we get
1/2 * .002 * 100 = .1
However, we will also consider the upwards bend of the curve.. Therefore, the answer has to be more than .1... Now, it can't be D because D is too large. D would actually equal to the area of the whole square if we don't multiply our number with 1/2... Therefore, it has to be C.
 
Snow Angel

Snow Angel

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can someone explain the following questions as soon as possible?

a) Question 2c in this paper, how should we find it and what do they expect?
 

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Snow Angel

Snow Angel

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c) help needed with question 5b in this paper.

:)please answer and explain the answer for these 3 questions as soon as possible with the correct answers. thank you
 

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S

Snackbox86

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usama321 said:
Using conservation of momentum, the velocity of the 1kg trolley would be
2*2 = 1* x
x = 4 m/s

now total kinetic energy of the two trolleys would be equal to the total energy released from the spring

1/2 * 2 * 4 + 1/2 * 1 * 16
= 12 J

For the 20th one, the strain energy would be the area under the graph...
By just taking a triangle, we get
1/2 * .002 * 100 = .1
However, we will also consider the upwards bend of the curve.. Therefore, the answer has to be more than .1... Now, it can't be D because D is too large. D would actually equal to the area of the whole square if we don't multiply our number with 1/2... Therefore, it has to be C.
Click to expand...



Thank you
 
B

boredome

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paper 4 june 2005 Q7 c) why did we use 1/10 not 1/9 ? I can't understand why it was solved that way in the marking scheme
 
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