• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Physics: Post your doubts here!

Messages
6
Reaction score
0
Points
11
i have dat cd worksheets nd ms which comes along with the chadha's Cambridge endorsed buk..let me know if u need it.
no budy im talking about "teachers resource CD ROM" it has answrs to end of chapters and exam style questions. i have the other cd i.e Coursebook CD
 

XPFMember

XPRS Moderator
Messages
4,555
Reaction score
13,290
Points
523
Assalamoalaikum wr wb!

I need some help with the significant figures..plz..

I'm confused about it. What we kearnt is it shud be having the same no. of sig. fig as in the data...but ms doesnt seem to follow this everytime :/
 
Messages
1,477
Reaction score
1,893
Points
173
Please post the answers.

(a) As the pole is in equilibrium,
C.W moments = A.C.W moments
mg*(1.5) = Tsin30*(2.5)
25*9.8*1.5 = Tsin30*(2.5)
T = 294 N

(b) Let the required force be 'R'
As the pole is in equilibrium,
Sum of upward forces = Sum of downward forces
Tcos30 = mg + R
294*cos30 = 25*9.8 + R
254.6 = 245 + R
R = 9.6 N

Hope this is right.
 
Messages
940
Reaction score
1,024
Points
103
Assalamoalaikum wr wb!

I need some help with the significant figures..plz..

I'm confused about it. What we kearnt is it shud be having the same no. of sig. fig as in the data...but ms doesnt seem to follow this everytime :/
mmm well i think u should follow the sig fig in the question it self mostly its given ! if they r given in 2 sgf then use that etc... !
 
Messages
1,477
Reaction score
1,893
Points
173
Assalamoalaikum wr wb!

I need some help with the significant figures..plz..

I'm confused about it. What we kearnt is it shud be having the same no. of sig. fig as in the data...but ms doesnt seem to follow this everytime :/
I felt exactly the same about the significant figures and the mark scheme. However I realised that always give the same number of or one better s.f than the question. Trust me, you wont get it wrong.
 

XPFMember

XPRS Moderator
Messages
4,555
Reaction score
13,290
Points
523
Waalaikumassalam wr wb!
Across P and Q is a variable resistor connected....and the resistance of it can be varied from zero to 50 ...

Now in series I remains the same...I=V/R

So when the resistance across the variable resistor is zero...the voltage is ofcourse going to be zero.

And when it is 50

I = V/R = 9 / 60

V across P and Q = I x R = 9/60 x 50 = 7.5 V

Hence the answer is B.

Note: In this case the units will get cancelled out in the end for resistance...and it's an MCQ so I haven't converted the kilo ohms to ohms.. Otherwise u are supposed to do that conversion first!
 
Messages
350
Reaction score
108
Points
43
State which combination, of any. Of monochromatic light and metal surface could give raise to photo-electric emission. Give a quantitative explanation of your answer.
 
Messages
350
Reaction score
108
Points
43
View attachment 4315 I'll be obliged if sum1 can solve this for me.
I will say T=250/sin30
1378bf52.jpg
 
Messages
45
Reaction score
9
Points
18
help me in mcq no 9 and 35 of may june 2002 paper 1..... explain in detail.
 

Attachments

  • 9702_s02_qp_1.pdf
    135.5 KB · Views: 5
Messages
59
Reaction score
39
Points
18
kindly explain q.10 worksheet 9 C part! how is the acceleration of the proton zero at right angles to the field? plz help

Why not at right angles to the field? Imagine the proton traveling between the two parallel plates in the figure above this question. There will be a downward force on it and you calculate it from the electric field strength as F/Q so answer is charge on proton X 2.40 × 10–6 V m–1.
 
Messages
1,477
Reaction score
1,893
Points
173
help me in mcq no 9 and 35 of may june 2002 paper 1..... explain in detail.
Q9:
As it is an elastic collision,
Total K.E after collision = Total K.E before collision
= (1/2)m(v)2 + (1/2)m(-v)2
= m(v)2
So, B is correct.

And in Q 35, just test all the combinations to find out the correct one.
 
Top