Mathematics: Post your doubts here!

[applepie1996]

applepie1996

this isnt the ethival way to do it... but still here u are
http://i1275.photobucket.com/albums/y444/Rutzaba/sleep_zpse14b1e9d.png

http://i1275.photobucket.com/albums/y444/Rutzaba/well_zps10150a0f.png

i have another question ?

 

[Rutzaba]

i have another question ?

my internets being soooooooooooooooooooooooooooo slow!
but go ahead try ur luck

 

[applepie1996]

applepie1996

this isnt the ethival way to do it... but still here u are
http://i1275.photobucket.com/albums/y444/Rutzaba/sleep_zpse14b1e9d.png

http://i1275.photobucket.com/albums/y444/Rutzaba/well_zps10150a0f.png

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w09_qp_31.pdfquestion 7 part 4

 

[Rutzaba]

i have another question ?

did u get this?
and do remember me in ur prayers k? this aint no frreee help

 

[applepie1996]

my internets being soooooooooooooooooooooooooooo slow!
but go ahead try ur luck

hope its good

 

[applepie1996]

did u get this?
and do remember me in ur prayers k? this aint no frreee help

InshaAllah
yeah i did

 

[Rutzaba]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w09_qp_31.pdfquestion 7 part 4

no more sketching plz... @dragonninja Dug littlecloud11

 

[applepie1996]

no more sketching plz... @dragonninja Dug littlecloud11

i just want you to explain it
don't sketch it
here is a rough sketch

 

[Rutzaba]

i just want you to explain it
don't sketch it
here is a rough sketch

a bit too rough

 

[Rutzaba]

as far as i think there will be twom circles made one with centre point 0,0 and modz = z-(0 +0i)
the second circle would be mid z-2 take it in general form ul get z- (2+0i) so 2 and zero as centre point.
this must be satisfied that the shaded region wud be in accordance with the in equality
the second thing is argument ... the region wch will be shaded will be between 0 and pi/4...
i no thisisnt a satisfactory explanation... but i have forgotten this chater completely ...

 

[applepie1996]

as far as i think there will be twom circles made one with centre point 0,0 and modz = z-(0 +0i)
the second circle would be mid z-2 take it in general form ul get z- (2+0i) so 2 and zero as centre point.
this must be satisfied that the shaded region wud be in accordance with the in equality
the second thing is argument ... the region wch will be shaded will be between 0 and pi/4...
i no thisisnt a satisfactory explanation... but i have forgotten this chater completely ...

its okay
atleast you tried
thanks

 

[Rutzaba]

its okay
atleast you tried
thanks

dun wrry imma finding professionals and bringig em here inshaAllah

 

[minie23]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s10_qp_12.pdf

Hey there ! I need a lil help for no. 4 ! Please help

 

[Hassi123]

you first plot points A and B on the diagram and i am assuming you know how to do that
next you find the mid point between A and B
you get -1/2-1/2i
this will be the centre of the circle
no you have to find the radius of the circle
find the distance between the two points using sqrt[(x2-x1)^2+(y2-y1)^2 and you get an answer
square root of answer will give you the radius

Ohh, i get all of it, but im still confused in one small thing, how do you find the point w^2 ( I know how to find mod and arg of w^2 but not the point )

 

[applepie1996]

Ohh, i get all of it, but im still confused in one small thing, how do you find the point w^2 ( I know how to find mod and arg of w^2 but not the point )

just square w

 

[Hassi123]

just square w

-.- haha thankyou so much!

 

[minie23]

this is sooooooooo easy... im not solving it fr ya i wan u to do it urself imma give u hins though

I cant figure out the first part

 

[Rutzaba]

I cant figure out the first part

frst part ? there are no parts in the quetion and on a second look it isnt as easy as i thot... imma solve completely fr ya

 

[PhyZac]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_qp_12.pdf

Hey there ! I need a lil help for no. 4 ! Please help

find the gradient of line AB
(3-1)/(-1-3)
= -1/2

now find the gradient of perpendicular line ( tht is L2)
2

find the line equation
(y-1) = 2(x-3)
y= 2x -5

find gradient of OB ( which is similar to L1)
(1-0)/(3-0)
= 1/3

find equation of L1
(y-3) = 1/3 (x-(-1))
3y - 9 = x + 1
3y = x + 10

Find intersection between L1 and L2
by simultaneous equation.

sub the yellow to blue
3(2x-5)=x +10
6x - 15 = x + 10
5x = 25
x = 5

now sub this to yellow
y=2(5) -5
y=5

C is (5,5)

 

[Rutzaba]

find the gradient of line AB
(3-1)/(-1-3)
= -1/2

now find the gradient of perpendicular line ( tht is L2)
2

find the line equation
(y-1) = 2(x-3)
y= 2x -5

find gradient of OB ( which is similar to L1)
(1-0)/(3-0)
= 1/3

find equation of L1
(y-3) = 1/3 (x-(-1))
3y - 9 = x + 1
3y = x + 10

Find intersection between L1 and L2
by simultaneous equation.

sub the yellow to blue
3(2x-5)=x +10
6x - 15 = x + 10
5x = 25
x = 5

now sub this to yellow
y=2(5) -5
y=5

C is (5,5)

lol much?