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hey guys, i need help in mechanics m/j 10
question 6 the 2nd part, why the acceleration is -3 and different than the first part which was 6? why the tension wasn't included in the calculation of the second part?
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_qp_41.pdf
y the string has slackened ?For the second part, the string has slackened and hence there will be no more tension in it. Clearly, since A is part of the original connected system,
when T=0, its acceleration will also change accordingly.
Hope this helps. Peace.
The particle B is resting on the ground, hence as A moves forward, the string is no longer taut. You can try to visualize this to convince yourself.y the string has slackened ?
Needs a helping hand!
View attachment 15481
Please someone help me for no. 11 (iii) whitecorp
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s09_qp_1.pdf
Thann you very much ! I was confusedYou can calculate the area under the line CD between x=2 and x=3 (which is a trapezium) and subtract from it the area under the curve y=x^3-6x^2+9x between x=2 and x=3 (you can do this through basic integration) to get your answer.
Hope this helps. Peace.
Thanku very muchtan(pi- x) = -tanx so ans is -k.
tan(pi/2 - x) = reflection of tanx means the ans will be inverse. 1/k
it is better explained in book from pages 172-179 core maths by s.bostock and s.chandler see there for clear understanding. by means of graphs
Thanx alot manView attachment 15387
omg sorry instead of all the pi i drew change it to 1/2pi..my fauly sorry :$
i hope this will help u !
ia answer to first part 1122KW just asking?Kuld u help me wid zis
ia answer to first part 1122KW just asking?
can any1 plz show me how to solve |x-2| +|3x-1|=0 and plot the graph too.........plz ur help will be highly appreciated.....
whitecorp
Indeed you're a boss! Thanks mate for everything.
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