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Mathematics: Post your doubts here!

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In quadrilateral ABCD, AB produced is perpendicular to DC produced. If <A = 44 and <C = 148, calculate <D and <B!
this one...
is there a diagram with this? i cant seem to understand how AB and DC can be perpendicular...
 
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It's easy:

Replace 'n' by a number from the table e.g. 3 and accordingly, the diagonals will be 0

1/p * 3(3-q) = 0
3/p (3-q) = 0
(9 - 3q)/p = 0
Take p to the other side... it multiplies and o* anything is o ;)
9 - 3q = 0
9 = 3q
q = 3 :)

Now take some other number:
1/p * 4(4-q) = 2
we know that q = 3
1/p * 4(1)
4/p = 2
2p = 4
p = 2 :D
 
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It's easy:

Replace 'n' by a number from the table e.g. 3 and accordingly, the diagonals will be 0

1/p * 3(3-q) = 0
3/p (3-q) = 0
(9 - 3q)/p = 0
Take p to the other side... it multiplies and o* anything is o ;)
9 - 3q = 0
9 = 3q
q = 3 :)

Now take some other number:
1/p * 4(4-q) = 2
we know that q = 3
1/p * 4(1)
4/p = 2
2p = 4
p = 2 :D
Seriously!!! -,-
Masha Allah
 
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