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Aga khan entry test 2012

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I know, right? i found Physics a bit difficult and intimidating too. The other parts- English, Bio, Sci Reas. & maths went pretty good :)
So, FINGERS CROSSED!! ;)
 
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Everybody has the same views about the paper. I guess the FSC guys will have an advantage over us. They must've been able to do the stuff in Chemistry and Physics that we had no clue about.
 
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Yeah. English was good but that comprehension was in no way like the one in the Sample paper. Wasn't hard. Just lengthy and boring:p Yeah they will prolly have the edge when it comes to the entry test but i guess we will cover it up in the Interview.
 
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u guys dint knew abt ortho para meta....it just refers to 2.4 irecting 3,5 directing groups....and yea grignard reagents was a thing from fsc also......well...there was a question which mentioned a formula of B(MAGNETIC FIELD)=SOMETHING DELTAd was it ampere's law?
 
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doppler shift ka formula parh k gaya tha....its anser was 2.2f
 
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Yea I think it was Ampere's law. I knew what Ortho Para Meta meant. Just didn't remember which was which :D
 
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yea mean ortho was carbon number 2 meta carbon numer and para carbn number...6..........there was one foolish question on the test in science reasoning asking where would a nitrate attach on benzene ring........though i marked ortho para....bt obviously we cant name the carbons as ortho para or meta if none of group is attached b4 and compound is just a benzene ring...wasnt it a wrong question ....wat do u think?
 
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yea mean ortho was carbon number 2 meta carbon numer and para carbn number...6..........there was one foolish question on the test in science reasoning asking where would a nitrate attach on benzene ring........though i marked ortho para....bt obviously we cant name the carbons as ortho para or meta if none of group is attached b4 and compound is just a benzene ring...wasnt it a wrong question ....wat do u think?
It was META man. This was a simple A'levels question. If it is a simple benzene ring. The nitro will take the first carbon and then further addition will happen at 3 and 5. Eventhough, it's called para-meta directing but we can also refer it to as only meta.

doppler shift ka formula parh k gaya tha....its anser was 2.2f
It was 1.2. :p I calculated it. You can do it right now. 0.5/(0.5-0.1). You get 1.2. Remember that the source was approaching, so you had to find the difference in the denominator.
 
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by the way ur calculation gives 1.25 as the anser....and i also remeber detector was also moviing so u hadd to add in the numerator also.....mayb u missd this bit......
 

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yea mean ortho was carbon number 2 meta carbon numer and para carbn number...6..........there was one foolish question on the test in science reasoning asking where would a nitrate attach on benzene ring........though i marked ortho para....bt obviously we cant name the carbons as ortho para or meta if none of group is attached b4 and compound is just a benzene ring...wasnt it a wrong question ....wat do u think?
bt he dint specified frther addition ,...and dats y i was cnfused k question is nt making sense.....cos obviously it can attach anywhere iinitially
 
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It was 1.2. :p I calculated it. You can do it right now. 0.5/(0.5-0.1). You get 1.2. Remember that the source was approaching, so you had to find the difference in the denominator.[/quote]

The formula is f=(vi+Vdetector)/(Vi-Vsource) when both are moving towards each other. 1.1/.5 =2.2
 
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It was 1.2. :p I calculated it. You can do it right now. 0.5/(0.5-0.1). You get 1.2. Remember that the source was approaching, so you had to find the difference in the denominator.

The formula is f=(vi+Vdetector)/(Vi-Vsource) when both are moving towards each other. 1.1/.5 =2.2[/quote]
Prolly, I didn't know this concept then. Who cares. I wasn't getting in anyways.
 
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i guess...we have discussed enuf........now tym to prepare 4 a2...........will u gyx be giving the PIEAS test ON 17 JUNE?
 
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