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  1. S

    P1 Maths October November 2007 question 4 (iii)

    Here is it: (i) A.P 1st term:a C.D: d a+4d=5th term a=14d=15th term G.P a=1st term ar=2nd term ar^2= 3rd term Now, (ii) a=a -(1) a+4d=ar -(2) a+14d=ar^2 -(3) we pick the 2nd equation r=a+4d/a equate eq.2 n 3 by subttituing the r=a+4d/a a+14d=a(a+4d/a)^2 it comes out to be a^2+14ad=a^2+8ad+16d^2...
  2. S

    ANY PREDICTIONS!!!

    yes there are high chances for electrochemistry ques this tym round in chem p2..neither in jun nor in nov09 it appeared..:)
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