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Recent content by zkapoor

  1. Z

    All chemistry Doubts here :)

    Dude, the question is which statement is NOT true
  2. Z

    All chemistry Doubts here :)

    Oh, whoops, sorry. I meant to write HOOCHC=CHCOOH
  3. Z

    All chemistry Doubts here :)

    Dude, you've got a double bond between your H's. I'm telling you, if you draw it out you'll get it. the answer is HOOC-CH2=CH2-COOH Think about it. 1 Carbon atom per half is being used for the carboxylic acid bond leaving exactly 1 carbon atom per half (or 1 pair in total) to make a double bond...
  4. Z

    All chemistry Doubts here :)

    My mistake, apologies. Keemoman is right Dibasic acids have 2 H+ ions and can hence form 2 varieties of salts - acidic (NaHSO4) or neutral (Na2SO4)
  5. Z

    All chemistry Doubts here :)

    Right, so the answer is that temperature increases. This is rather simple. When they speak of temperature UNLESS THEY SAY OTHERWISE (or in a diagram position the thermometer in the product) they mean temperature of the surroundings. Think of it like this, how can you measure the temperature...
  6. Z

    May/June 2011 exams

    I agree with xIshtar, looking for A* across the board but it's too soon to say now... 5 papers left and a whole subject to go
  7. Z

    May/June 2011 exams

    Physics - not that bad really, though I can't say I loved paper 33. English language - Paper 2 was fine, paper 3 was also pretty good though I might've messed up this one thing... Add math - We'll see Chem - Paper 63 wasn't bad, though I practically wrote an essay for the last question =P Paper...
  8. Z

    Any one there giving Additional Mathematics?

    It's not that hard, haven't you done relative velocity before? Okay, I'll break it down. (i) you need the velocity in terms of i and j. Since it's going north east (at an angle of 45 degrees to the north) you can draw an isosceles right angled triangle (i and j are equal). (15root2)^2 = 2x^2...
  9. Z

    All chemistry Doubts here :)

    Doesn't matter. The answer is chromatography - as long as the products are different they will rise to different heights on a chromatogram. Boiling point will probably also work in this case (though it's not in the mark scheme)
  10. Z

    All chemistry Doubts here :)

    Firstly, H has a double bond with C ? And secondly, you've only shown one (COOH) chain. I would suggest, if you're getting confused with this type of question draw it out and count the bonds. Btw 1 mole of acid makes 2 moles of H+ ions basically means that the anion of the acid has a double...
  11. Z

    All chemistry Doubts here :)

    @XIshtar - DAMN, that is lucky. So you take bio, eco, chem and some variation of lit which doesn't require paper 5 i assume? Lucky. Lit P5 is a NIGHTMARE. And I have additional mathematics to do as well
  12. Z

    All chemistry Doubts here :)

    The key, I would say, is that the eth is 1 mol/dm^3 as well, so the same number of H+ ions are present in the solution. It's just harder for the ones in eth to dissociate from the compound SO the reaction is slower SO lower slope
  13. Z

    All chemistry Doubts here :)

    What, you mean why there's a same final volume? You have to assume (actually it might even be stated) that the ethanoic acid used is in excess. So the final volume of Hydrogen produced will be the same. However, since it's a weaker acid the SPEED of the reaction will be less so the slope of the...
  14. Z

    Any one there giving Additional Mathematics?

    UAE, huh? I've heard that's a pretty fun place. To be honest, I haven't done too much. All you really can do is practice. I've done 4 practice papers till date, though I've been spending a lot of time revising for Lit paper 5 and Chem cause I'm weaker in those subjects. How are you preparing...
  15. Z

    All chemistry Doubts here :)

    It definitely isn't A or D. Bromine and therefore the vapour is brown and since it's a covalent compound it'll be soluble in covalent/organic (basically non polar) solvents. The other two, I really have no clue. You're posting an A level question in an IGCSE forum bro
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