• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Recent content by Rimsha Noor1

  1. R

    Chemistry M/J 2015 Paper 52

    you have to draw lines on the graph to read a value.
  2. R

    PHYSICS P42 2015 !

    the paper was so hard i left 10 marks straight away.
  3. R

    and stop stalking me -.- :p

    and stop stalking me -.- :p
  4. R

    ayyeee ye kon online agaya :P

    ayyeee ye kon online agaya :P
  5. R

    Physics: Post your doubts here!

    i got it. Thank you so much! :)
  6. R

    Physics: Post your doubts here!

    http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Physics%20(9702)/9702_w13_qp_11.pdf Question 8. Why cant we just add up the speeds and divide them by 2? :|
  7. R

    thanks. same to you :)

    thanks. same to you :)
  8. R

    Sorry? :S did i say anything like that? :S :/

    Sorry? :S did i say anything like that? :S :/
  9. R

    it was really good. wbu?

    it was really good. wbu?
  10. R

    inbox ya habibiti.

    inbox ya habibiti.
  11. R

    INBOXX

    INBOXX
  12. R

    I'm new here and can anyone help me out with this please :)

    ohh achaaa .. half life of background plus source is about 2.8 days ( 52 counts) count rate of only background is almost 14. so 52-14 = 38. use the graph to find the half life of this 38 ( source) , it would be around 1. so 2.8-1 = 1.8 that's the answer.
  13. R

    I'm new here and can anyone help me out with this please :)

    (a) this is because the sample has almost completely decayed and the reason why the count rate increases at times, it might be due to background radiation.
  14. R

    jana hai phr kl school?

    jana hai phr kl school?
  15. R

    taurrass <3

    taurrass <3
See more
Top