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Recent content by markskoop

  1. M

    Need SHM notes

    please if anyone has SHM and oscillation notes plz upload it.. thnk u!
  2. M

    Physics: Post your doubts here!

    need help with this one
  3. M

    Physics: Post your doubts here!

    here final velocity = 0 inital velocity = v e-field = E so or, f = eE or, ma= eE or a = eE\m------1) now v^2 = u^2 + 2as since its abt to stop so its deceleration 0 = v^2-2ax v^2= 2 * eE\m *x so x= (v^2 * m)\(2eE) so answer is D
  4. M

    Physics: Post your doubts here!

    this one toooo plz explain
  5. M

    Physics: Post your doubts here!

    plz help
  6. M

    Physics: Post your doubts here!

    May june 11 P23 question number 6 "b" need help... some one plz reply soon
  7. M

    how ws math xams guys paper 62 ??!!

    guys.....wht do u think would b the threshold for stat????
  8. M

    how was MAths 9709 p62 ???

    YA.....i agree wid u deepa...........bt my bad...even i forgot to write d same..............can u guess how much marks wil be deducte????
  9. M

    Physics: Post your doubts here!

    A cricket ball is thrown vertically upward with a speed of 15.0 meters per second. What is the velocity of the cricket ball when it passes through a point 8.0 meters above the cricketer's hands? Please help me this one...as soon as possible!!!!!!
  10. M

    Maths P62

    Guys if u have any prediction, notes that might help in this final moment dan please share.. and even confusions!!!
  11. M

    Chem P33

    Chem P33 tomaro.. if any of your have any guesses or helps reagarding tomaros xam please post....really secared!! please help!!!!!!!!
  12. M

    Mathematics: Post your doubts here!

    hey.i really got a confusion in writing the intervals while makin cumulative frequency grap.............the upper limit of each interval should be inclusive or exclusive??xplain me wid xamples.............and do we need to arange the upper and lower limits whil calculating...
  13. M

    Mathematics: Post your doubts here!

    for 7(i). p(at least one 3)=p(x>=1) 1-p(x=0) 1-(9C0*(5/6)^9)=0.806 for 7(ii). we don't know the no.of throws which we suppose as n...... so instead of 9 in d first solution,we take it as n....then 1-(9C0*(5/6)^n)>0.or,,,(5/6)^n<0.1 then u can take log in both sides and do or simply frm...
  14. M

    Mathematics: Post your doubts here!

    [email protected] first answer would be (12!/4!*2!)=9979200.this is because 4 R are being repeated and 2 E being repeated. next answer would be (9!/2!)=181440 .....as its said R must be together so taking 4 R as 1,the total arrangement would be 9! and den as 2 E are being repeated in dis...
  15. M

    Mathematics: Post your doubts here!

    nq is n(1-p)...i.e...q is 1-probability(p)......ya and normal distribution is always used if both np>5 and nq>5..if either of d values is less dan 5 den,,,binomial distribution is preferable rather than normal....... :)
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