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Recent content by Gunner7

  1. G

    Mechanics M1: Post your doubt here

    Let's assume Car's Driving force is 'X', at the Bottom F =X and and at the top,F = 3 x (X) = 3X Power = F x V ,At bottom Power = 6 x (X) = 6X , At top Power = 6X x 5 = 30X Power = F x V, 30X = 3X x V , V at top = 30X / 3X = 10 , and then u solve it normally like (i)
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    Mechanics M1: Post your doubt here

    distance moved by Stolen car in first 3 sec = 40 x 3 = 120 m, Stolen car u=40 v=40 a=o ,S= 40t + 0.5 x 0 x t^2 , S= 40t Police car , u=o a = 8 ,S = 0 x t + 0.5 x 8 x t^2 ,S=4t^2 now we equal distance moved by two cars but add 120 m to distance moved by stolen car ( In first 3 sec) 4t^2 =...
  3. G

    Pure Maths 12 today........

    3 I guess
  4. G

    Mechanics M1: Post your doubt here

    Well Actually I'm better in P1 than P4,Help me here please http://www.xtremepapers.com/papers/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20(9709)/9709_w04_qp_4.pdf (question 6) Same Idea came again in 2010 or 2011 (not sure) and I dont understand it at all.
  5. G

    Pure Maths 12 today........

    How did you solve it please ?
  6. G

    Pure Maths 12 today........

    k,-k,2k
  7. G

    Pure Maths 12 today........

    9/2-x or 9/2+x ,I got volume 9 pie and vector question first part angle was 24.1 ?
  8. G

    Pure Maths 12 today........

    Show that in the 2nd question was kind of easy,still took me about 10 mins to get it
  9. G

    Pure Maths 12 today........

    The range was not given,I Had to get it then place it as the domain of inverse,domain of function was x>3 not the inverse ? can't really remember if you still remember the function we can solve it again :D
  10. G

    Pure Maths 12 today........

    Yup there was equal sign but I actually can't find it here on the Keyboard :D
  11. G

    Pure Maths 12 today........

    Yup A was 2, and domain was x>-1 or x>1 cant remember the sign
  12. G

    Pure Maths 12 today........

    The question was about the minimum value of the 'Gradient' not the curve,So DY/DX of the curve is the equation of the tangent,D^2Y/DX^2 is the second deff of curve but first deff of Gradient,so you get D^2Y/DX^2 and equal it to 0,get the X substitute it into DX/DY to get minimum value of...
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    Pure Maths 12 today........

    get Dy/Dx ,Substitute x=3 (I guess) to get the Gradient of tangent,substitute (3,1) to get C (not sure about the Coordinates tho,but that's the idea)
  14. G

    Pure Maths 12 today........

    Probably 2, 1 for wrong limits and 1 for wrong answer.
  15. G

    Pure Maths 12 today........

    Yup got K= -1
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