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Recent content by DominicD

  1. D

    How was Chemistry Paper 12?

    Yes, that is correct. But baked clay is not SiCl4, therefore it is not simple molecule.
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    How was Chemistry Paper 12?

    Baked clay is giant molecular structure, it is silica, SiC. SiCl4 is liquid at room temperature.
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    No teacher for Further Maths

    I think it is best for you to not take F. maths. I'm a further math student myself, and thankfully I have a very capable and experienced teacher. It really isn't a subject you can just study by yourself, or with an inexperienced teacher.
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    How was chemistry paper 23?

    Yes, there's only one solution that actually changed colour, but if you look at this paper, question 4, part b : http://olevel.sourceforge.net/papers/9701/9701_s12_qp_21.pdf The answer given is actually colourless to colourless, and purple to colourless. So, I wrote the colour for all the...
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    How was chemistry paper 23?

    I wrote everything colourless to colourless, except for KMnO4, purple to colourless and the K2Cr2O7, orange to orange.
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    How was chemistry paper 23?

    x is 1/15, but they asked for moles of all the reactants and products. So reactants = (4-1/15) mol, products = (2+1/15) mol. mass of CO2 by population = 1.20 x 10^7 tonnes. last part = 1.39 x 10^11 km. What did you guys wrote for the colour changes for the organic part? Rather easy, this...
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    Physics Paper 23

    I think that works. I however used v^2=2(gsin15)(0.28/sin15), well it's the same anyway.
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    Physics Paper 23

    I wasn't expecting that much of drawing and calculations for gradients. >__> Tedious work. It is definitely helium-3, isotope of helium-4.
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    Physics Paper 23

    I think generally the paper isn't hard. It is different and for some people, it looks tricky. :P
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    Physics Paper 23

    The expression of I is, I=E/(R+r), E is the y-intercept = 5.8V, power dissipated when I=1.6A is P=VI = 2.9x1.6 = 4.64W, and lastly the efficiency part is just VI/EI x100% = 50%
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    Physics Paper 23

    For the resultant velocity, just connect the tail of the wind velocity to the head of the plane velocity, then connect them both with a resultant velocity. You'll get some sort of triangle shape. It's hard to put it in words. The new height of BC is still the same as AB, I think it's around...
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    Physics Paper 23

    When it comes to scale drawing, Cambridge are usually very strict about it. Just use the usual vector addition method. Btw I'm from Malaysia.
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    Physics Paper 23

    Thanks. I got 32N for R too. :) As for the resultant velocity, I used the scale and I got 11.3cm, equivalent to 226ms-1.
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    Physics Paper 23

    I'm pretty sure from the first part, the R is 48N, and v=12ms-1. So the k must be 4 for part i.
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    Physics Paper 23

    What did you all get for the Resistive force?
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