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okay imagine the beam enteringCan you please explain why are you multiplying 0.018 by e^(-48*10-2)2 i
I understand e^ part but why is 0.018 being multiplied to it.
shouldn't it just be this:
0.012=e^((-48*10-2)2)
i just dont understand why you're using the coefficient alpha thats been calculated in the first part of the question
Because itn't the formula:
I=Io e^-αx
the Intensity cancel out, but what i dont understand is that why are we using the α and the µ at the same time in this question.
i'm so confused.
There will be three phases.
1- It will move through the layer of fat. As it moves, it will attenuate and intensity will decrease. (e^48 x*10-2)
2- It will be reflected at the tissue boundary. But some of it will be transmitted thru the muscle tissue. (0.018 of the total is reflected).
3- It will move across the layer of fat and will be equally attenuated once more (e^48 x 2*102)
So you just have to multiply all these three phases in order to find the intensity detected.
The detected intensity is already given (0.012) so put it's value in the equation which is like.
Intensity detected = not attenuated x reflected x not attenuated
In short, some of the beam is also 'transmitted and NOT REFLECTED' at the tissue boundary. In this case only 0.018 of it is reflected. The rest is not so obvio it is not detected.
To get an accurate value, this should also be considered.