Mathematics: Post your doubts here!

[Thought blocker]

Absolutely right bro... Thanks a lot... Helped me a ton

anytime

 

[Thought blocker]

notes on s2? xpf member

 

[brightmoonlight00362]

Hi can anyone tell me how to solve this question:
Two motor-cyclists A and B are travelling, in the same direction, in different lanes on a motorway. A has a constant acceleration of 0.5 ms^-2 and B has a
constant speed of 30ms^-1. At time t = 0, A is 375 metres ahead of B and is travelling with speed 10 m^-1. The motion of the two motor-cyclists may be modelled by that of two particles moving along parallel straight lines. B overtakes A at time t = T1, where time is measured in seconds. Show that t = T, is a solution of the equation:
t^2-80t + 1500 = 0
Interpret the other solution, t = T2, of this equation. Find the values of T1 and T2 and hence find the speed of A at these times.
thank you in advance.

 

[Thought blocker]

Hi can anyone tell me how to solve this question:
Two motor-cyclists A and B are travelling, in the same direction, in different lanes on a motorway. A has a constant acceleration of 0.5 ms^-2 and B has a
constant speed of 30ms^-1. At time t = 0, A is 375 metres ahead of B and is travelling with speed 10 m^-1. The motion of the two motor-cyclists may be modelled by that of two particles moving along parallel straight lines. B overtakes A at time t = T1, where time is measured in seconds. Show that t = T, is a solution of the equation:
t^2-80t + 1500 = 0
Interpret the other solution, t = T2, of this equation. Find the values of T1 and T2 and hence find the speed of A at these times.
thank you in advance.

https://answers.yahoo.com/question/index?qid=20160913171709AALesl0

 

[brightmoonlight00362]

https://answers.yahoo.com/question/index?qid=20160913171709AALesl0

aye thanks alot

 

[Thought blocker]

aye thanks alot

Welcome.

 

[brightmoonlight00362]

A girl sitting on a wooden board slides down a line of greatest slope, which is inclined at 10degrees to the horizontal, on a snow-covered mountain. The combined mass of the girl and the board is 65 kg, and the magnitude of the frictional force between the board and the slope is 125 N. Air resistance may be ignored.
a)Show that the coefficient of friction between the board and the slope is 0.20 (2 s.f), and verify that the girl and the board are slowing down.

b) The girl passes a point A travelling at 5ms. Calculate her speed at the point B, where B is 40m down the slope form A.

c) Later in the day the girl, still sitting on the board, is pulled up the same slope, with constant speed, by a rope inclined at 30degrees above the horizontal. The surface of the slope may now be assumed to be smooth. Calculate the magnitude of the force exerted on the board by the slope.
( answers are (b) 3.17ms^-1 and (c)599N )

need help in part c please since i cant get my answer right.Thank you in advance
i looked up the question online but however couldnt manage to understand it.

 

[i_try9621]

Anyone help me how to create a cumulative frequency table using this?

 

[Thought blocker]

A girl sitting on a wooden board slides down a line of greatest slope, which is inclined at 10degrees to the horizontal, on a snow-covered mountain. The combined mass of the girl and the board is 65 kg, and the magnitude of the frictional force between the board and the slope is 125 N. Air resistance may be ignored.
a)Show that the coefficient of friction between the board and the slope is 0.20 (2 s.f), and verify that the girl and the board are slowing down.

b) The girl passes a point A travelling at 5ms. Calculate her speed at the point B, where B is 40m down the slope form A.

c) Later in the day the girl, still sitting on the board, is pulled up the same slope, with constant speed, by a rope inclined at 30degrees above the horizontal. The surface of the slope may now be assumed to be smooth. Calculate the magnitude of the force exerted on the board by the slope.
( answers are (b) 3.17ms^-1 and (c)599N )

need help in part c please since i cant get my answer right.Thank you in advance
i looked up the question online but however couldnt manage to understand it.

https://uk.answers.yahoo.com/question/index?qid=20090301083744AABmXz9

 

[Thought blocker]

View attachment 61162 Anyone help me how to create a cumulative frequency table using this?

https://www.facebook.com/groups/mathsrevision.examsolutions/
I am sorry, i have forgotten this thing completely xD Though post ur doubt there, in the link, hope so u get enough help

 

[i_try9621]

https://www.facebook.com/groups/mathsrevision.examsolutions/
I am sorry, i have forgotten this thing completely xD Though post ur doubt there, in the link, hope so u get enough help

thanks for that

 

[Thought blocker]

thanks for that

Welcome.

 

[techgeek]

help in question 5

 

[Thought blocker]

View attachment 61166

help in question 5

(i)substitute value of x and y in the implicit equation
(ii) differentiate this implicit equation and equate it to -6 and simplify to get eqn in temrs of k and c
use eqn in (i) and this eqantion to solve for k and c.

 

[techgeek]

(i)substitute value of x and y in the implicit equation
(ii) differentiate this implicit equation and equate it to -6 and simplify to get eqn in temrs of k and c
use eqn in (i) and this eqantion to solve for k and c.

can you please solve just the first part?

 

[Thought blocker]

can you please solve just the first part?

6(9) + 4 + 2k = c
58 + 2k = c

 

[Thought blocker]

e^(ln3^2) = 9 techgeek
e^(ln2^2) = 4

 

[musiclover gurl]

Hi...I was working the paper Nov 15 P 23 when I encountered these problems....Can someone help me, please?
(Encircled parts are where I have difficulties in doing)

 

[Thought blocker]

Hi...I was working the paper Nov 15 P 23 when I encountered these problems....Can someone help me, please?
(Encircled parts are where I have difficulties in doing)
View attachment 61174 View attachment 61175 View attachment 61176

5(ii)
Take any random value for a in the iterations. For example, 2.34567 then insert that in the a, then keep repeating till u get converging value, that will be your alpha, it will converge to 1.477.
6(b)
10 + 3(-1) = 7 least
10 + 3(1) = 13 greatest
Least value of cos is -1 and greatest is 1.
7(i)
use quotient rule to solve it, and simplify it to get in the form asked.

*error in the pic* : in the first step, its y = expression.

 

[techgeek]

When solving partial fractions, in 10 (i) , how do we get A and B as 2?
I, somehow, get a very different value for A and B