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Mathematics: Post your doubts here!

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Can someone give me the solution for the second part of this question? The answer is 16km.
 

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Can someone give me the solution for the second part of this question? The answer is 16km.

Did you round off or some stuff? Cause I'm getting an answer close to it (15.7km). Btw I do not believe we get this in cambridge examinations( especially because neither integration/differenciation nor applying motion equations is to be required)

Edit: What i did was, displacement of bird=displacement of car 1.
Displacement= 16*40/41=15.6km
40/41 is the time taken for car1 to meet car2.
 
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3. The random variable X is normally distributed with mean µ and variance 21.0. Given that P(X > 10.0) = 0.7389,(w06_6) find the value of µ.please help me out with this problem anyone! aren't we supposed to use (X-mean)/sd but the answer came wrong!
 
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Well then, :( I cant even do the first part! Help?

It's hard to copy paste pheta everytime, I'm using pheta=@ ok?
sin (2@+@)= sin2@cos@+ cos2@sin@ -------1
This you get in formula sheet.

Then what is sin2@ and cos2@?
sin 2@= 2sin@cos@
cos 2@= 1-2sin^2 @

Replace in first equation
2sin@cos@cos@ +(1-2sin^2 @)sin@
2sin@cos^2 @+(1-2sin^2 @)sin@
----------->cos^2 @= 1-sin^2 @
2sin@(1-sin^2 @)+ (1-2sin^2 @) sin@
2sin@-2sin^3 @+ sin@ -2sin^3 @
=3sin@ -4sin^3 @
Easy? It's all in the formula sheet you are given, you just have to substitute.

For part 2, Relatively easy you just replace x by what is given and simplify.

For part 3, solve sin 3@= 3/4
you get valueS of @ and replace in x= 2sin@/3^0.5
 
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