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C ?
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C ?
http://www.allaboutcircuits.com/vol_1/chpt_1/7.htmlElectrons are negatively charged, and as such they will move from an area of lower potential to an area of higher potential. Also, they will move away from the negative terminal and towards the positive terminal (conventional current moves in the opposite direction, and in reality this flow of electrons is the current that actually transfers energy across the circuit).
Therefore, the current will go from the terminal on the right to the top-right corner of the circuit, move to the bottom right (point Y), move across the resistor to (point X) and then back to the positive terminal of the battery. Therefore, the current will be from Y to X (i.e. option C or D).
Furthermore, if the current is 4.8 Amperes, using the formula
Q = I * t
(Where Q is the charge that flows through a point in "t" seconds when a current of I Amperes is flowing)
we can say that
I = Q/t
So the current is equal to the rate of flow of charge past a point. Okay, so this has units Coulombs/Second, which is what we want (answer is also in same units).
So if the current is 4.8 Amperes, the rate of flow of charge is 4.8 Coulombs/Second.
How much is this? Let's see.
The charge on any 1 electron is 1.6 * 10⁻¹⁹ Coulombs. Therefore, to make up 1 Coulomb, we need 1/(1.6 * 10⁻¹⁹) = 6.25 * 10¹⁸ electrons.
But if 1 Coulomb is 6.25 * 10¹⁸ electrons per second, 4.8 Coulombs should be 4.8 * (6.25 * 10¹⁸) electrons per second, right?
Carrying out this calculation, we get 4.8 * (6.25 * 10¹⁸) = 30.0 * 10¹⁸ = 3.0 * 10¹⁹ electrons/second.
This flows in the direction of Y to X, therefore our answer must be A.
Hope this helped!
Good Luck for all your exams!
there are a series of formulae to apply in this one. you must make sense first.
density = mass/volume
he is moving up at rate of 50cm/s means 0.5m/s
if he is at constant speed there is no resultant force so all forces cancel out so
LOL I GOT 392 then I thought I might had made some mistake LOLhe is moving up at rate of 50cm/s means 0.5m/s
his mass is 80KG so his weight is almost 785N
power = work done per second= Force * distance/second = 785*0.5=392=0.39KW
Acha!!if he is at constant speed there is no resultant force so all forces cancel out so
air resistance = weight
kv=mg
v=mg/k
kinetic energy = 1/2 mv² = 1/2 m (mg/k)² = 1/2 m³g²/k² = m³g²/2k²
m1g is weight at one side. m2g is weight at other side. their difference is balanced by motor.
Let the distance between the double slit and the screen be 1m initially.
s12_s12Can someone explain q 17,29,30 of mj 12 v 12
And question 40,20,7,3 of mj 07
PLZZ
Let the distance between the double slit and the screen be 1m initially.
When the distance is increased BY 2m the NEW distance is 3m.
Using the formula:
Wavelength= (fringe seperation x distance between the double slits)/ distance between the screen and the slits.
Wavelenght=600nm=600x10^-9m.
Fringe seperation= 3mm= 3x10^-3m
Distance between screen and slits= 3m (1+2)
Distance between the double slit=?
Put these values in the formula, the final answer is 6x10^-4m =0.6mm
Hence the answer is B.
3:Can someone explain q 17,29,30 of mj 12 v 12
And question 40,20,7,3 of mj 07
PLZZ
x=dλ/a
x=dλ/a
in case 1,
1E-3=d600E-9 / a
so d=1667a
in case 2:
3E-3=(d+2)*600E-9 / a
a=(d+2)*600E-9 / 3E-3
a= (1667a + 2)2E-4
a-0.333a=4E-4
a=4E-4 / 0.667
=6E-4m=0.6mm
this was the only way it came in my mind. maybe ZaqZainab or someone else can tell a shorter way. if no shortway comes into your mind atleast do complete it through complete procedure.
E denotes?x=dλ/a
in case 1,
1E-3=d600E-9 / a
so d=1667a
in case 2:
3E-3=(d+2)*600E-9 / a
a=(d+2)*600E-9 / 3E-3
a= (1667a + 2)2E-4
a-0.333a=4E-4
a=4E-4 / 0.667
=6E-4m=0.6mm
this was the only way it came in my mind. maybe ZaqZainab or someone else can tell a shorter way. if no shortway comes into your mind atleast do complete it through complete procedure.
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