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As physics p1 MCQS YEARLY ONLY.

dumb human

dumb human

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leosco1995 said:
June 2005
=========

Q1. C.

Fact, basic stuff.

Q2. C

Rearrange the equation to make k the subject, so k = F/rv.

= (kgms^-1)/(m * ms^-1)
= kgm^-1s^-1

Q3.B

A reasonable estimate for an athelete running a 100m race is approximately 10 seconds.

K.E = 1/2 * 80 * 10^2
= 4000 J

Q4. C

Principle speed value = 16
Uncertainty = (0.1/40) + (0.05/2.50) * 16 = 0.36

We always round off the uncertainty value to one s.f., so it becomes 0.4

So the answer is 16 +/ 0.4

Q5. A

The length of the pulse is how long you see the change in the Y-axis. It's for 2cm, meaning 2 μs.

Q6. D

Easy stuff. To find acceleration you take the gradient of a velocity-time graph.

Q7. B

The acceleration during the motion of a falling ball will always be constant, i.e. 9.81 ms^-2. Since they told us to take upwards as positive and the gravitational force acts downwards, this is actually -9.81 ms^-2.

Q8. D

Distance is area of the graph. Class 4 stuff. :p

Q9. A

Acceleration doesn't act in the horizontal direction so it's value is therefore 0.

B is wrong because the object has velocity throughout the motion.
C is wrong because of B, the resultant velocity will be non-zero because of the horizontal velocity being non-zero.
D is just nonsense.

Q10. A

B, C and D are Newton's 2nd, 3rd and 1st law respectively.

Q11. A

Momentum is always conserved so we use that formula. Also when the objects stick on impact, the total mass will be the sum of the individual masses. Let 'm' be the mass of one of the objects.

60m + (40 * -m) = 2mx (where x is the speed of the masses after impact).
20m = 2mx
x = 10 because m cancel out.

Q12. C

Fact. D is wrong because it gravity is the point through which gravity APPEARS to act.

Q13. A

The forces are shown in this picture: http://www.xtremepapers.com/community/attachments/moe-png.12069/ (Thanks a ton to Unicorn for this).

(5*2) + (2*10) - (3*20) = 30 Nm anti-clockwise.

Q14. D

Resolve the horizontal 4N and vertical 3N component to get a 5N component parallel to the diagonal 4N component. Since the 5N force would be greater, the resultant force would be 1N in its direction.

Q15.B

K.E will be constant because the velocity and mass are constant (velocity beacause it says in the question).

P.E will start from a high value and decrease uniformly because the height is decreasing uniformly.

Q16. C

The gradient of an energy/time graph is power since P = E/t. So we are looking for the point where the gradient is the steepest. This is from 2s-3s, so the gradient there is (40-10)/1 = 30W.

Q17. B

P.E = mgh.

They have given the density and volume from which we can calculate the mass. g is 9.81 and h is 3.0m.

Q18. A

Fact.

Q19. C

Brownian motion, the molecules of liquid collide with the molecules of the pollen grains.

Q20. A

Let a regular extension be 'x'. In parallel, the extension is divided by the # of springs and the opposite for a 'series' extension.

Extension in X is e/2.
Extension in Y is e/2 + e/2 = e.
Extension in Z is e/2 + e = 1.5e.

The order is X -> Y -> Z.

Q21. D

You need to know these graphs. Brittle (glass) is just a straight steep line, rubber is like that of graph X (note that they don't obey Hooke's law) and Y is that of steel, a ductile material.

Q22. D

Let their Young Modulus be equal to 'E'. They have to have the same YM (same material), so..

E = FL/Ax (where x is extension).
F = EAx/L (E and x don't matter here because they're constant).

For P, F = A/l
For Q, F = 0.5A/2l

Ratio is 4:1.

Q23. A

Fact, all transverse waves travel at the same speed in a vaccuum.

Q24. B

You need to know a reasonable estimate of the wavelength of visible light, e.g. 500 nm.

# of wavelengths in ONE metre is 1/(500 nm) 2.0 * 10^6. This is in the order of 10^6, so B is right.

Q25. B

Use ratio of intensity and amplitude.

(I1/I2) = (a1/a2)^2

1/2 = (A/x)^2

x = √2A

Q26. B

Fact, sort of.

Q27. D

Distance between 2 maxima = 0.5λ.


So 1λ = 30 mm.

F = v/λ
F = 3.0 * 10^8 / 30 mm
F = 2.0 * 10 Hz.

Q28. B

Formula is x = λr/q

According to this equation, decreasing 'q' will increase 'x'. A has nothing to do with 'x'.

Q29. B

For 2nd order, d sin θ = 600 nm * 2, which is

d sin θ = 1200 nm

For 3rd order,

d sin θ = 3λ

Since d has to be the same and the angle is also the same, we can equate the 2 equations.

3λ = 1200 nm
λ = 400 nm.

Q30. D

E = V/d.
= 900 / (4 mm)
= 2.3 * 10^3 N/C

Q31. C

Fact.

Q32. C

The area is irrelevant to this question, because Q = I * t (there is nothing to do with area in this formula).

Q = 10 * 1 = 10 C

Since one electron has a charge of 1.6 * 10^-19 C, 10 C has 6.3 * 10^19 electrons.

Q33. D

Originally, R = ρL/A

Now, the length is doubled BUT the volume is the same. This means the area has to be halved. Mathematically proving this:

Volume is length * breadth * height, so:

2lbh = v

Since Area = lb
A = 2lb
lb = 0.5A

Anyway, new resistance will be 2ρL/0.5 = 4R.

Q34. D

A is wrong because Q is a thermistor/semi-conductor/etc.
B is wrong because the resistance decreases.
C is wrong because the resistances are the same at 1.9 (same V:I) ratio.
D is right because using I^2 * R proves this is correct.

Q35. B

Fact.

Q36. D

In parallel, voltage is the same so V2 = V3.

And terminal voltage V = V1 + V3

Rearranging this gives

V - V1 = V3

Q37. At X the voltmeter is connected directly so it gets the full 4V. At Y we use the potential divider formula to find the voltage:

V = 4 * (10/20) = 2V

B is the only graph that shows this correctly.

Q38. C

Easy stuff.

Q39. B

The range of α particles is approximately 0 - 5cm. In this question, they've given us values in mm, so we can say the range is 0 - 500 mm.

B is the safest maximum range.

Q40. C

The nucleon number decreases by (4+4+0) so it becomes 209.
The proton number decreases by (2+2-1) so it becomes 82.
Click to expand...


Thought blocker can you explain Question 13) ?
 
Thought blocker

Thought blocker

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H

Hanona

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Thought blocker said:
Aww.. sis you don't know this ?? I am sorry for the delay..
Resistance in 1 wire of 800m =0.005 * 800 = 4 ohms
resistance in 2 wires = 4 ohms * 2 = 8 ohms
V = IR = 0.6 * 8 = 4.8 V
Min voltage = 16 + 4.8 = 20.8 V
Click to expand...
ahhh!! got it :D thank you ! I really dont know what we all have done without you solving our doubts !^_^ youre awesome
 
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