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28)AS SALAMO ALAIKUM
can some one plzz help me with q 28 , 37 & 39
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w04_qp_1.pdf
it's simple!AS SALAMO ALAIKUM
can some one plzz help me with q 28 , 37 & 39
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w04_qp_1.pdf
Guys.. Any help???http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_s11_qp_32.pdf
HELP!!! how do we calculate the enthalpy change??!! :$
Question 2 b (iii)
Wait, I have loads of work... Will come to your house, or will do it tomorrowThought blocker dude! I need your help in one thing of enthalpy calculation if online do reply?
OR ANY ONE CAN REPLY IF AVALIABLE!
well i am not sure about 9 amd 11http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w06_qp_1.pdf
Plz help me with 3 questions from o/n/6
Q9-C
Q11-B
Q25-B
Thanku
bro it is simple calculation needed! you know na my maths probs so. and this is enthalpy calculations! it will hardly take 2 min for youWait, I have loads of work... Will come to your house, or will do it tomorrow
Post it, if I would be free, I'd solve it. Go on!bro it is simple calculation needed! you know na my maths probs so. and this is enthalpy calculations! it will hardly take 2 min for you
As you know that for finding entalpy we substract ==> product - reactantPost it, if I would be free, I'd solve it. Go on!
Link ?As you know that for finding entalpy we substract ==> product - reactant
than solve this for me .. hey me bhu gaya kiska doubt tha ruk do min ab
i got sweet sugar post ques 9 cmon bro do it!
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w06_qp_1.pdf
Plz help me with 3 questions from o/n/6
Q9-C
Q11-B
Q25-B
Thanku
where the square come from in ques 11q9
q 11 assume the moles used up were x.
so u have equation
4= x^2/(1-x)^2
taking square roots on both sides we have
2=x/(1-x)
2-2x=x
2/3 =x
since volume is not mentioned you can assume it to be 1 dm^3
Okay, here goes:
sorry but muje kuch samaj me nahi ayaOkay, here goes:
CO2(g) + H2(g) -> CO(g) + H2O(g)
CO2 is being broken, so instead of -283, we take +283
H2O is being formed, so we use -286
BUT it is being formed in gaseous state, not liquid state, so we also take +44.
283 + 44 - 286 = +41.
So the answer is C
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